हिंदी

Evaluate: sin35∘cos55∘+cos35∘sin55∘cosec210∘-tan280∘ - Mathematics

Advertisements
Advertisements

प्रश्न

Evaluate:

`(sin35^circ cos55^circ + cos35^circ sin55^circ)/(cosec^2 10^circ - tan^2 80^circ)`

मूल्यांकन

उत्तर

`(sin35^circ cos55^circ + cos35^circ sin55^circ)/(cosec^2 10^circ - tan^2 80^circ)`

= `(sin35^circ.cos(90^circ - 35^@) + cos35^circ.sin(90^circ - 35^circ))/(cosec^2(90^circ - 80^circ) - tan^2 80^circ)`

= `(sin35^circ.sin35^circ + cos35^circ.cos35^circ)/(sec^2 80^circ - tan^2 80^circ)`

= `(sin^2 35^circ + cos^2 35^circ)/(sec^2 80^circ - tan^2 80^circ)`

= `1/1`

= 1

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 21: Trigonometrical Identities - Exercise 21 (C) [पृष्ठ ३२९]

APPEARS IN

सेलिना Mathematics [English] Class 10 ICSE
अध्याय 21 Trigonometrical Identities
Exercise 21 (C) | Q 10 | पृष्ठ ३२९

वीडियो ट्यूटोरियलVIEW ALL [2]

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×