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Write condensed orbital notation of electronic configuration of the following element: Calcium (Z = 20) - Chemistry

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प्रश्न

Write condensed orbital notation of electronic configuration of the following element:

Calcium (Z = 20)

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उत्तर

Element Condensed orbital notation
Calcium (Z = 20) [Ar] 4s2
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अध्याय 4: Structure of Atom - Exercises [पृष्ठ ५४]

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बालभारती Chemistry [English] 11 Standard
अध्याय 4 Structure of Atom
Exercises | Q 6. (L)(f) | पृष्ठ ५४

संबंधित प्रश्न

Using s, p, d notations, describe the orbital with the following quantum numbers n = 1, l = 0.


Choose the correct option.

p-orbitals are _________ in shape.


State Hund’s rule of maximum multiplicity with a suitable example.


Write orbital notations for the electron in orbitals with the following quantum numbers.

n = 2, l = 1


Write orbital notations for the electron in orbitals with the following quantum numbers.

n = 3, l = 2


Write condensed orbital notation of electronic configuration of the following element:

Oxygen (Z = 8)


Write condensed orbital notation of electronic configuration of the following element:

Chlorine (Z = 17)


The electronic configuration of oxygen is written as 1s2 2s2 \[\ce{2p^2_{{x}}}\] \[\ce{2p^1_{{y}}}\] \[\ce{2p^1_{{z}}}\] and not as 1s2 2s2 \[\ce{2p^2_{{x}}}\], \[\ce{2p^2_{{y}}}\] \[\ce{2p^0_{{z}}}\], Explain.


Using the concept of quantum numbers, calculate the maximum numbers of electrons present in the ‘M’ shell. Give their distribution in shells, subshells, and orbitals.


Indicate the number of unpaired electrons in \[\ce{Si}\] (Z = 14).


Indicate the number of unpaired electron in:

Cr (Z = 24)


Which one of the following orders is CORRECT in case of energy of the given subshells?

P: n = 4; l = 3

Q: n = 5; I = 1

R: n = 5; l = 0

S: n = 4; l = 2


The three electrons have the following set of quantum numbers:

X = 6, 1, −1, `+1/2`

Y = 6, 0, 0, `+1/2`

Z = 5, 1, 0, `+1/2`

Identify the CORRECT statement.


Which of the following has a greater number of electrons than neutrons?

(Mass number of Mg, C, O and Na is 24, 12, 16 and 23 respectively).


Which of the following properties of atom could be explained correctly by Thomson Model of atom?


The number of radial nodes for 3p orbital is ______.


Which of the following sets of quantum numbers are correct?

  `n` `l` `m_l`
(i) 1 1 +2
(ii) 2 1 +1
(iii) 3 2 –2
(iv) 3 4 –2

Which of the following statements concerning the quantum numbers are correct?

(i) Angular quantum number determines the three dimensional shape of the orbital.

(ii) The principal quantum number determines the orientation and energy of the orbital.

(iii) Magnetic quantum number determines the size of the orbital.

(iv) Spin quantum number of an electron determines the orientation of the spin of electron relative to the chosen axis.


Nickel atom can lose two electrons to form \[\ce{Ni^{2+}}\] ion. The atomic number of nickel is 28. From which orbital will nickel lose two electrons.


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

1s, 2s, 3s, 2p


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

5p, 4d, 5d, 4f, 6s


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, solve the questions given below:

Which of the following orbitals has the lowest energy?

4d, 4f, 5s, 5p


The electronic configuration of valence shell of Cu is 3d104s1 and not 3d94s2. How is this configuration explained?


Match species given in Column I with the electronic configuration given in Column II.

Column I Column II
(i) \[\ce{Cr}\] (a) [Ar]3d84s0
(ii) \[\ce{Fe^{2+}}\] (b) [Ar]3d104s1
(iii) \[\ce{Ni^{2+}}\] (c) [Ar]3d64s0
(iv) \[\ce{Cu}\] (d) [Ar] 3d54s1
  (e) [Ar]3d64s2

Choose the INCORRECT statement


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