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प्रश्न
Write condensed orbital notation of electronic configuration of the following element:
Chlorine (Z = 17)
उत्तर
Element | Condensed orbital notation |
Chlorine (Z = 17) | [Ne] 3s2 3p5 |
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संबंधित प्रश्न
Using s, p, d notations, describe the orbital with the following quantum numbers n = 1, l = 0.
Using s, p, d notations, describe the orbital with the following quantum numbers n = 3; l =1.
Choose the correct option.
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Choose the correct option.
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State Heisenberg uncertainty principle.
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Write condensed orbital notation of electronic configuration of the following element:
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Write condensed orbital notation of electronic configuration of the following element:
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Write condensed orbital notation of electronic configuration of the following element:
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Write a note on ‘Principal Quantum number.
Indicate the number of unpaired electrons in \[\ce{Si}\] (Z = 14).
The designation of a subshell with n = 6 and l = 2 is ____________.
Which of the following options does not represent ground state electronic configuration of an atom?
Which of the following properties of atom could be explained correctly by Thomson Model of atom?
Number of angular nodes for 4d orbital is ______.
Orbital angular momentum depends on ______.
Which of the following statements concerning the quantum numbers are correct?
(i) Angular quantum number determines the three dimensional shape of the orbital.
(ii) The principal quantum number determines the orientation and energy of the orbital.
(iii) Magnetic quantum number determines the size of the orbital.
(iv) Spin quantum number of an electron determines the orientation of the spin of electron relative to the chosen axis.
Calculate the total number of angular nodes and radial nodes present in 3p orbital.
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Based upon the above information, arrange the following orbitals in the increasing order of energy.
5p, 4d, 5d, 4f, 6s
The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.
Based upon the above information, solve the questions given below:
Which of the following orbitals has the lowest energy?
4d, 4f, 5s, 5p
The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.
Based upon the above information, solve the questions given below:
Which of the following orbitals has the lowest energy?
5p, 5d, 5f, 6s, 6p
Match species given in Column I with the electronic configuration given in Column II.
Column I | Column II |
(i) \[\ce{Cr}\] | (a) [Ar]3d84s0 |
(ii) \[\ce{Fe^{2+}}\] | (b) [Ar]3d104s1 |
(iii) \[\ce{Ni^{2+}}\] | (c) [Ar]3d64s0 |
(iv) \[\ce{Cu}\] | (d) [Ar] 3d54s1 |
(e) [Ar]3d64s2 |
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