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Answer the following: Find the modulus and argument of a complex number and express it in the polar form. 6 − i - Mathematics and Statistics

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प्रश्न

Answer the following:

Find the modulus and argument of a complex number and express it in the polar form.

6 − i

बेरीज

उत्तर

Let z = 6 − i

∴ a = 6, b = − 1, a > 0, b < 0

∴ |z| = r

= `sqrt("a"^2 + "b"^2)`

= `sqrt(6^2 + (-1)^2)`

= `sqrt(36 + 1)`

= `sqrt(37)`

Here (6, −1) lies in 4th quadrant

∴ amp (z) = θ = `2pi + tan^-1 ("b"/"a")`

= `2pi + tan^-1 ((-1)/6)`

∴ the polar form of z = r(cos θ + i sin θ)

= `sqrt(37)(cos theta + "i" sin theta)`

where θ = `2pi + tan^-1 (-1/6)`

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Argand Diagram Or Complex Plane
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Complex Numbers - Miscellaneous Exercise 1.2 [पृष्ठ २२]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board
पाठ 1 Complex Numbers
Miscellaneous Exercise 1.2 | Q II. (6) (ii) | पृष्ठ २२

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