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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Arrange the compounds of the following set in order of reactivity towards SN2 displacement: 1-Bromo-3-methylbutane, 2-Bromo-2-methylbutane, 2-Bromo-3-methylbutane - Chemistry

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प्रश्न

Arrange the compounds of the following set in order of reactivity towards SN2 displacement:

1-Bromo-3-methylbutane, 2-Bromo-2-methylbutane, 2-Bromo-3-methylbutane

रासायनिक समीकरणे/रचना
लघु उत्तर

उत्तर

The SN2 reaction involves the formation of a transition state with the carbon atom surrounded by 5 additional atoms (groups). A transition state requires minimum steric interactions. The most suitable substrates for SN2 reactions are 1° alkyl halides, followed by 2° and 3° alkyl halides. The order of reactivity towards SN2 is 1° > 2° > 3°> aryl halide. Based on this, the order will be

\[\begin{array}{cc}
\ce{CH3}\phantom{...............................}\ce{CH3}\phantom{.................}\ce{CH3}\phantom{.....}\\
\phantom{.....}|\phantom{...................................}|\phantom{....................}|\phantom{............}\\
\ce{\underset{1-Bromo-3-methylbutane}{H3C - CH - CH2 - CH2Br} > \ce{CH3 - CH - CH - CH3} > \ce{CH3 - C - CH2 - CH3}}\\
\phantom{.......................}|\phantom{..........................}|\\
\phantom{.........................}\ce{\underset{2-Bromo-3-methylbutane}{Br}\phantom{.........}\ce{\underset{2-Bromo-2-methylbutane}{Br}}}\
\end{array}\]

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पाठ 10: Haloalkanes and Haloarenes - Exercises [पृष्ठ ३११]

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एनसीईआरटी Chemistry [English] Class 12
पाठ 10 Haloalkanes and Haloarenes
Exercises | Q 16.2 | पृष्ठ ३११

संबंधित प्रश्‍न

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(A) 2° > 3° > 1° 

(B) 3° > 2° > 1°

(C) 3° > 1° > 2°

(D) 1° > 3° > 2°


Given reasons: SN1 reactions are accompanied by racemization in optically active alkyl halides.


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(iv) Molecularity of reaction is two.


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(I)
(II)
(III)

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The following questions are case-based questions. Read the passage carefully and answer the questions that follow:

Nucleophilic Substitution:
Nucleophilic substitution reaction of haloalkane can be conducted according to both SN1 and SN2 mechanisms. SN1 is a two-step reaction, while SN2 is a single-step reaction. For any haloalkane, which mechanism is followed depends on factors such as the structure of haloalkane, properties of leaving group, nucleophilic reagent and solvent.

Influences of solvent polarity:
In SN1 reaction, the polarity of the system increases from the reactant to the transition state, because a polar solvent has a greater effect on the transition state than the reactant, thereby reducing activation energy and accelerating the reaction. In SN2 reaction, the polarity of the system generally does not change from the reactant to the transition state, and only charge dispersion occurs. At this time, the polar solvent has a great stabilizing effect on Nu than the transition state, thereby increasing activation energy and slow down the reaction rate. For example, the decomposition rate (SN1) of tertiary chlorobutane at 25°C in water (dielectric constant 79) is 300000 times faster than in ethanol (dielectric constant 24).

The reaction rate (SN2) of 2-bromopropane and NaOH in ethanol containing 40% water is twice slower than in absolute ethanol. Hence the level of solvent polarity has an influence on both SN1 and SN2 reactions but with different results. Generally speaking, a weak polar solvent is favourable for SN2 reaction, while a strong polar solvent is favourable for SN1. Generally speaking, the substitution reaction of tertiary haloalkane is based on SN1 mechanism in solvents with a strong polarity (for example ethanol containing water).

Answer the following questions:

(a) Why racemisation occurs in SN1? (1)

(b) Why is ethanol less polar than water? (1)

(c) Which one of, the following in each pair is more reactive towards SN2 reaction? (2)

(i) CH3 – CH2 – I or CH3CH2 – Cl

(ii)

OR

(c) Arrange the following in the increasing order of their reactivity towards SN1 reactions: (2)

(i) 2-Bromo-2-methylbutane, 1-Bromo-pentane, 2-Bromo-pentane

(ii) 1-Bromo-3-methylbutane, 2-Bromo-2-methylbutane, 2-Bromo-3- methylbutane


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Which alkyl halide from the following pair would you expect to react more rapidly by an SN2 mechanism? Explain your answer.

\[\begin{array}{cc}\ce{CH3CH2CHCH3}\\\phantom{...}|\\\phantom{....}\ce{Br}\end{array}\] or \[\begin{array}{cc}\phantom{.....}\ce{CH3}\\\phantom{..}|\\\ce{H3C - C - Br}\\\phantom{..}|\\\phantom{....}\ce{CH3}\end{array}\]


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