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प्रश्न
Calculate the value of A, if cos 3A. (2 sin 2A - 1) = 0
उत्तर
cos 3A (2 sin 2A – 1) = 0
cos 3A = 0 and 2 sin 2A – 1 = 0
cos 3A = cos90° and 2 sin 2A = 1
3A = 90° and sin 2A = `(1)/(2)`
A = 30° and sin 2A = sin 30°
A = 30°
2A = 30°
⇒ A = 15°
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