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प्रश्न
Choose the correct alternative:
Equation of a circle which passes through (3, 6) and touches the axes is
पर्याय
x2 + y2 + 6x + 6y + 3 = 0
x2 + y2 − 6x − 6y − 9 = 0
x2 + y2 − 6x − 6y + 9 = 0
x2 + y2 − 6x + 6y − 3 = 0
उत्तर
Equation of a circle which passes through (3, 6) and touches the axes is x2 + y2 − 6x − 6y + 9 = 0
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