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Choose the correct alternative: If the lines 2x − 3y = 5 and 3x − 4y = 7 are the diameters of a circle of area 154 sq. units, then find the equation of the circle - Mathematics and Statistics

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प्रश्न

Choose the correct alternative:

If the lines 2x − 3y = 5 and 3x − 4y = 7 are the diameters of a circle of area 154 sq. units, then find the equation of the circle

पर्याय

  • x2 + y2 − 2x + 2y = 40

  • x2 + y2 − 2x + 2y = 40

  • x2 + y2 − 2x + 2y = 47

  • x2 + y2 − 2x − 2y = 40

MCQ

उत्तर

x2 + y2 − 2x + 2y = 47

Explanation:

Centre of circle = Point of intersection of diameters.

Solving 2x – 3y = 5 and 3x – 4y = 7, we get x = 1, y = - 1

Centre of the circle C (h, k) = C (1, –1)

Area = 154

∴ πr2 = 154

∴ `22/7 xx "r"^2 = 154`

∴ `"r"^2 = 154 xx 7/22` = 49

∴ r = 7

∴ equation of the circle is

(x - 1)2 + (y + 1)2 = 72

∴ x2 + y2 − 2x + 2y = 47

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Different Forms of Equation of a Circle
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पाठ 6: Circle - Miscellaneous Exercise 6 [पृष्ठ १३६]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board
पाठ 6 Circle
Miscellaneous Exercise 6 | Q I. (2) | पृष्ठ १३६

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