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प्रश्न
Construct a triangle with sides 5 cm, 6 cm, and 7 cm and then another triangle whose sides are `3/5` of the corresponding sides of the first triangle.
उत्तर
1. Draw a line AB = 5 cm and draw a ray from A and taking A as centre cut an arc at C of 6 cm and taking B as centre cut an arc of 7 cm at C
2. Draw AX such that ∠BAX is an acute angle.
3. Cut 5 equal arcs AA1, A1A2, A2A3, A3A4, and A4A5.
4. Join A5 to B and draw a line through A3 parallel to A5B which meets AB at B'.
Here, `AB' = 3/5AB`
5. Now draw a line through B' parallel to BC which joins AC at C'.
Here, `B'C' = 3/5BC "and" AC' = 3/5AC`
Thus, AB'C' is the required triangle.
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