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प्रश्न
`cos(tan sqrt(x + 1))`
उत्तर
Let y = `cos(tan sqrt(x + 1))`
`"dy"/"dx" = "d"/"dx" cos(tan sqrt(x + 1))`
= `- sin(tan sqrt(x + 1)) "d"/"dx" (tan sqrt(x + 1))`
= `-sin(tan sqrt(x + 1))sec^2 sqrt(x + 1) * "d"/"d"(x + 1)^(1/2)`
= `-sin(tan sqrt(x + 1))sec^2 sqrt(x + 1) 1/2 (sqrt(x + 1))^((-1)/2)`
∴ `(-1)/(2sqrt(x + 1)) * sin(tan sqrt(x + 1)) * sec^2 (sqrt(x + 1))`
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