मराठी

Define a Binary Operation *On the Set {0, 1, 2, 3, 4, 5} Asshow that Zero is the Identity for this Operation and Each Element A ≠ 0 of the Set is Invertible with 6 − A Being the Inverse Of A. - Mathematics

Advertisements
Advertisements

प्रश्न

Define a binary operation *on the set {0, 1, 2, 3, 4, 5} as

a * b = `{(a+b, "if a+b < 6"), (a + b - 6, if a +b >= 6):}`

Show that zero is the identity for this operation and each element a ≠ 0 of the set is invertible with 6 − a being the inverse of a.

उत्तर

Let X = {0, 1, 2, 3, 4, 5}.

The operation * on X is defined as:

a * b = `{ (a+b, "if a+b < 0"), (a+ b - 6, "if a + b >= 6"):}`

An element e ∈ X is the identity element for the operation *, if a * e = a = e * a ∀ a ∈ X

For a ∈ X we observed that

a * 0 = a + 0 =a   [a ∈ X ⇒ a + 0 < 6]

0 * a = 0 + a = a        [a ∈ X ⇒ 0 + a < 6]

:. a * 0 =a = 0 * a ∀ a ∈ X

Thus, 0 is the identity element for the given operation *.

An element a ∈ X is invertible if there exists b∈ X such that a * b = 0 = b * a.

ie `{(a+b = 0= b + a, if a + b < 6),(a+6 - 6= 0=b + a - 6, if a+b >= 6):}`

i.e.,

a = −b or b = 6 − a

But, X = {0, 1, 2, 3, 4, 5} and ab ∈ X. Then, a ≠ −b.

b = 6 − a is the inverse of a &mnForE; a ∈ X.

Hence, the inverse of an element a ∈Xa ≠ 0 is 6 − a i.e., a−1 = 6 − a.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Relations and Functions - Exercise 1.5 [पृष्ठ ३०]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 12
पाठ 1 Relations and Functions
Exercise 1.5 | Q 14 | पृष्ठ ३०

संबंधित प्रश्‍न

Let * be a binary operation, on the set of all non-zero real numbers, given by `a** b = (ab)/5` for all a,b∈ R-{0} that 2*(x*5)=10


Let * be a binary operation on the set of rational numbers as follows:

(i) − 

(ii) a2 + b2

(iii) ab 

(iv) = (− b)2

(v) a * b = ab/4

(vi) ab2

Find which of the binary operations are commutative and which are associative.


Consider a binary operation * on defined as a3 + b3. Choose the correct answer.

(A) Is * both associative and commutative?

(B) Is * commutative but not associative?

(C) Is * associative but not commutative?

(D) Is * neither commutative nor associative?


Consider the binary operations*: ×→ and o: R × R → defined as a * b = |a - b| and ab = a, &mnForE;ab ∈ R. Show that * is commutative but not associative, o is associative but not commutative. Further, show that &mnForE;abc ∈ Ra*(b o c) = (ab) o (a * c). [If it is so, we say that the operation * distributes over the operation o]. Does o distribute over *? Justify your answer.


Given a non-empty set X, let *: P(X) × P(X) → P(X) be defined as A * B = (A − B) ∪ (B −A), &mnForE; AB ∈ P(X). Show that the empty set Φ is the identity for the operation * and all the elements A of P(X) are invertible with A−1 = A. (Hint: (A − Φ) ∪ (Φ − A) = Aand (A − A) ∪ (A − A) = A * A = Φ).


Number of binary operations on the set {ab} are

(A) 10

(B) 16

(C) 20

(D) 8


Determine whether the following operation define a binary operation on the given set or not : '×6' on S = {1, 2, 3, 4, 5} defined by

a ×6 b = Remainder when ab is divided by 6.


Determine whether the following operation define a binary operation on the given set or not :

\[' +_6 ' \text{on S} = \left\{ 0, 1, 2, 3, 4, 5 \right\} \text{defined by}\] 
\[a +_6 b = \begin{cases}a + b & ,\text{ if a} + b < 6 \\ a + b - 6 & , \text{if a} + b \geq 6\end{cases}\]


Is * defined on the set {1, 2, 3, 4, 5} by a * b = LCM of a and b a binary operation? Justify your answer.


Let '*' be a binary operation on N defined by a * b = 1.c.m. (a, b) for all a, b ∈ N

Check the commutativity and associativity of '*' on N.


Check the commutativity and associativity of the following binary operation 'o' on Q defined by \[\text{a o b }= \frac{ab}{2}\] for all a, b ∈ Q ?


Check the commutativity and associativity of the following binary operation '*' on Q defined by a * b = a + ab for all ab ∈ Q ?


Check the commutativity and associativity of the following binary operation  '*' on R defined by a * b = a + b − 7 for all ab ∈ R ?


 Check the commutativity and associativity of the following binary operation'*' on Q defined by a * b = ab + 1 for all a, b ∈ Q ?


If the binary operation o is defined by aob = a + b − ab on the set Q − {−1} of all rational numbers other than 1, shown that o is commutative on Q − [1].


Show that the binary operation * on Z defined by a * b = 3a + 7b is not commutative ?


On Z, the set of all integers, a binary operation * is defined by a * b = a + 3b − 4. Prove that * is neither commutative nor associative on Z.


On Q, the set of all rational numbers a binary operation * is defined by \[a * b = \frac{a + b}{2}\] Show that * is not associative on Q.


Let * be a binary operation on Z defined by
a * b = a + b − 4 for all a, b ∈ Z Find the invertible elements in Z ?


Let A = R0 × R, where R0 denote the set of all non-zero real numbers. A binary operation '⊙' is defined on A as follows (a, b) ⊙ (c, d) = (ac, bc + d) for all (a, b), (c, d) ∈ R0 × R :

Show that '⊙' is commutative and associative on A ?


Let 'o' be a binary operation on the set Q0 of all non-zero rational numbers defined by   \[a o b = \frac{ab}{2}, \text{for all a, b} \in Q_0\].

Show that 'o' is both commutative and associate ?


Let R0 denote the set of all non-zero real numbers and let A = R0 × R0. If '*' is a binary operation on A defined by

(a, b) * (c, d) = (ac, bd) for all (a, b), (c, d) ∈ A

Find the identity element in A ?


Let A  \[=\] R  \[\times\] R and \[*\]  be a binary operation on defined by \[(a, b) * (c, d) = (a + c, b + d) .\] . Show that \[*\] is commutative and associative. Find the binary element for \[*\] on A, if any.


Consider the binary operation 'o' defined by the following tables on set S = {a, bcd}.

o  a b c d
a a a a a
b a b c d
c a c d b
d a d b c

Show that the binary operation is commutative and associative. Write down the identities and list the inverse of elements.


Define a binary operation * on the set {0, 1, 2, 3, 4, 5} as \[a * b = \begin{cases}a + b & ,\text{ if a  + b} < 6 \\ a + b - 6 & , \text{if a + b} \geq 6\end{cases}\]

Show that 0 is the identity for this operation and each element a ≠ 0 of the set is invertible with 6 − a being the inverse of a.


Define a binary operation on a set.


Write the inverse of 5 under multiplication modulo 11 on the set {1, 2, ... ,10}.


Q+ denote the set of all positive rational numbers. If the binary operation a ⊙ on Q+ is defined as \[a \odot = \frac{ab}{2}\] ,then the inverse of 3 is __________ .


Let * be a binary operation defined on set Q − {1} by the rule a * b = a + b − ab. Then, the identify element for * is ____________ .


For the binary operation * defined on R − {1} by the rule a * b = a + b + ab for all a, b ∈ R − {1}, the inverse of a is ________________ .


Let A = ℝ × ℝ and let * be a binary operation on A defined by (a, b) * (c, d) = (ad + bc, bd) for all (a, b), (c, d) ∈ ℝ × ℝ.
(i) Show that * is commutative on A.
(ii) Show that * is associative on A.
(iii) Find the identity element of * in A.


Fill in the following table so that the binary operation * on A = {a, b, c} is commutative.

* a b c
a b    
b c b a
c a   c

Let A = `((1, 0, 1, 0),(0, 1, 0, 1),(1, 0, 0, 1))`, B = `((0, 1, 0, 1),(1, 0, 1, 0),(1, 0, 0, 1))`, C = `((1, 1, 0, 1),(0, 1, 1, 0),(1, 1, 1, 1))` be any three boolean matrices of the same type. Find A ∧ B


Choose the correct alternative:

Subtraction is not a binary operation in


Choose the correct alternative:

In the set R of real numbers ‘*’ is defined as follows. Which one of the following is not a binary operation on R?


Which of the following is not a binary operation on the indicated set?


a * b = `((a + b))/2` ∀a, b ∈ N is


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×