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Differentiate the following w.r.t. x: tan-1(2x521-x5) - Mathematics and Statistics

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प्रश्न

Differentiate the following w.r.t. x:

`tan^-1((2x^(5/2))/(1 - x^5))`

बेरीज

उत्तर

Let y = `tan^-1((2x^(5/2))/(1 - x^5))`

Put `x^(5/2)` = tanθ

Then θ = `tan^-1(x^(5/2))`

∴ y = `tan^-1((2tanθ)/(1 - tan^2θ))`

= tan–1(tan2θ)

= 2θ

= `2tan^(–1)(x^(5/2))`

Differentiating w.r.t. x, we get

`"dy"/"dx" = "d"/"dx"[2tan^-1(x^(5/2))]`

= `2"d"/"dx"[tan^-1(x^(5/2))]`

= `2 xx (1)/(1 + (x^(5/2))^2)."d"/"dx"(x^(5/2))`

= `(2)/(1+ x^5) xx (5)/(2)x^(3/2)`

= `(5xsqrt(x))/(1 + x^5)`

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Differentiation
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Differentiation - Exercise 1.2 [पृष्ठ ३०]

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