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प्रश्न
Equation of the line passing through (1, 2) and parallel to the line y = 3x – 1 is ______.
पर्याय
y + 2 = x + 1
y + 2 = 3 (x + 1)
y – 2 = 3 (x – 1)
y – 2 = x – 1
उत्तर
Equation of the line passing through (1, 2) and parallel to the line y = 3x – 1 is y – 2 = 3 (x – 1).
Explanation:
Given equation is y = 3x – 1
Slope = 3
Slope of the line passing through the given point (1, 2) and parallel to the given line = 3
So, the equation of the required line is y – 2 = 3(x – 1)
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| Column C1 | Column C2 |
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(iii) x – y –1 = 0 |
| (d) Equally inclined to the axes is | (iv) 3x – 4y – 1 = 0 |
