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प्रश्न
Express the following in terms of log 2 and log 3: `"log"(26)/(51) - "log"(91)/(119)`
उत्तर
`"log"(26)/(51) - "log"(91)/(119)`
= `"log"(2 xx 13)/(3 xx 17)-"log"(7 xx 13)/(7 xx 17)`
= `"log"(2 xx 13)/(3 xx 17)-"log"(13)/(17)`
= log13 + log2 - log3 - log17 - log13 + log17
= log2 - log3.
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