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प्रश्न
If 3( log 5 - log 3 ) - ( log 5 - 2 log 6 ) = 2 - log x, find x.
उत्तर
3( log 5 - log 3 ) - ( log 5 - 2 log 6 ) = 2 - log x
⇒ 3log 5 - 3log 3 - log 5 + 2 log( 2 x 3 ) = 2 - log x
⇒ 3log 5 - 3log 3 - log 5 + 2log2 + 2log3 = 2 - log x
⇒ 2log5 - log3 + 2log2 = 2 - log x
⇒ 2log5 - log3 + 2log2 + log x = 2
⇒ log52 - log 3 + log22 + log x = 2
⇒ log`([ 25 xx 4 xx x]/[3]) = 2`
⇒ log`((100x)/3) = 2`
⇒ `(100x)/3 = 10^2`
⇒ `x/3 = 1`
⇒ x = 3.
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