Advertisements
Advertisements
प्रश्न
factorise : ab(x2 + y2) - xy (a2 + b2)
उत्तर
ab(x2 + y2) - xy (a2 + b2)
= abx2 + aby2 - a2xy - b2xy
= abx2 - a2xy + aby2 - b2xy
= abx2 - a2xy - b2xy + aby2
= ax (bx - ay) - by (bx - ay)
= (bx - ay)(ax - by)
APPEARS IN
संबंधित प्रश्न
Factorise the following expression:
7x − 42
Factorise the following expression:
7a2 + 14a
Factorize the following:
2l2mn - 3lm2n + 4lmn2
Factorize the following:
ax2y + bxy2 + cxyz
Factories by taking out common factors :
ab(a2 + b2 - c2) - bc(c2 - a2 - b2) + ca(a2 + b2 - c2)
Factorise : `x^2 + 1/x^2 - 3`
Factorise:
(2a - 3)2 - 2 (2a - 3) (a - 1) + (a - 1)2
Factorise : x4 + y4 - 3x2y2
Factorise : 3 - 5x + 5y - 12(x - y)2
Find the value of : `[(6.7)^2 - (3.3)^2]/[6.7 - 3.3]`
Factorise : 15x4y3 - 20x3y
Factorise : (a+ 2b) (3a + b) - (a+ b) (a+ 2b) +(a+ 2b)2
factorise : 6x3 - 8x2
factorise:
9a (x − 2y)4 − 12a (x − 2y)3
factorise : x2y - xy2 + 5x - 5y
Factorise the following by taking out the common factors:
2x5y + 8x3y2 - 12x2y3
Factorise the following by taking out the common factors:
24m4n6 + 56m6n4 - 72m2n2
Factorise:
`y^2 + (1)/(4y^2) + 1 - 6y - (3)/y`
Factorise the following by taking out the common factor
18xy – 12yz