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Factorise the Following by Taking Out the Common Factors: 24m4n6 + 56m6n4 - 72m2n2 - Mathematics

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प्रश्न

Factorise the following by taking out the common factors:
24m4n6 + 56m6n4 - 72m2n2

बेरीज

उत्तर

24m4n6 + 56m6n4 - 72m2n2 
Here, the common factor is 8m2n2
Dividing throughout by 3a, we get

`(24"m"^4"n"^6)/(8"m"^2"n"^2) + (56"m"6"n")/(8"m"^2"n"^2) - (72"m"^2"n"^2)/(8"m"^2"n"^2)`
= 3m2n4 + 7m4n2 - 9
∴ 24m4n6 + 56m6n4 - 72m2n2
= 8m2n2(3m2n4 + 7m4n2 - 9).

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पाठ 5: Factorisation - Exercise 5.1

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फ्रँक Mathematics [English] Class 9 ICSE
पाठ 5 Factorisation
Exercise 5.1 | Q 1.05
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