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प्रश्न
Factorise the following by taking out the common factors:
2x5y + 8x3y2 - 12x2y3
उत्तर
2x5y + 8x3y2 - 12x2y3
Here, the common factor is 2x2y.
Dividing throughout by 2x2y, we get
`(2x^5y)/(2x^2y) + (8X^3y^2)/(2x^2y) - (12x^2y^3)/(2x^2y)`
= x3 + 4xy - 6y2
∴ 2x5y + 8x3y2 - 12x2y3
= 2x2y(x3 + 4xy - 6y2).
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