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प्रश्न
Factorise:
`x^2 + 1/(4x^2) + 1 - 7x - 7/(2x)`
उत्तर
`x^2 + 1/(4x^2) + 1 - 7x - 7/(2x)`
= `(x)^2 + 1/(2x)^2 + 2 xx x xx 1/(2x) - 7( x + 1/(2x))`
= `( x + 1/(2x))^2 - 7( x + 1/(2x))`
= `( x + 1/(2x))( x + 1/(2x) - 7)`
= `( x + 1/(2x))( x - 7 + 1/(2x))`
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