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प्रश्न
Factorise : `(9a)^2 + 1/(9a)^2 - 2 - 12a + 4/(3a)`
उत्तर
`(9a)^2 + 1/(9a)^2 - 2 - 12a + 4/(3a)`
= `(3a)^2 + 1/(3a)^2 - 2 xx 3a xx 1/(3a) - 4( 3a - 1/(3a))`
= `( 3a - 1/(3a))^2 - 4( 3a - 1/(3a))`
= `(3a - 1/(3a))[( 3a - 1/(3a)) - 4]`
= `( 3a - 1/(3a))( 3a - 4 - 1/(3a))`
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