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प्रश्न
Factorise the following by taking out the common factors:
4x2y3 - 6x3y2 - 12xy2
उत्तर
4x2y3 - 6x3y2 - 12xy2
Here, the common factor is 2xy2.
Dividing throughout by 2xy2, we get
`(4x^2y^3)/(2xy^2) - (6x^3y^2)/(2xy^2) - (12xy^2)/(2xy^2)`
= 2xy - 3x2 - 6
∴ 4x2y2 - 6x3y2 - 12xy2
= 2xy2[2xy - 3x2 - 6].
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