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Find the Equation to the Straight Line Which Cuts off Equal Positive Intercepts on the Axes and Their Product is 25. - Mathematics

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प्रश्न

Find the equation to the straight line which cuts off equal positive intercepts on the axes and their product is 25.

थोडक्यात उत्तर

उत्तर

The equation of the line with intercepts a and b is \[\frac{x}{a} + \frac{y}{b} = 1\].

Here, a = b and ab = 25

\[\therefore a \times a = 25\]

\[ \Rightarrow a^2 = 25\]

\[ \Rightarrow a = 5 \left( \because \text { we are to take only positive value of intercepts } \right)\]

Hence, the equation of the required line is

\[\frac{x}{5} + \frac{y}{5} = 1\] 

 \[ \Rightarrow x + y = 5\]
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Straight Lines - Equation of Family of Lines Passing Through the Point of Intersection of Two Lines
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पाठ 23: The straight lines - Exercise 23.6 [पृष्ठ ४७]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 23 The straight lines
Exercise 23.6 | Q 5 | पृष्ठ ४७

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