Find the equation of the parabola in the cases given below: End points of latus rectum (4, – 8) and (4, 8) - Mathematics

Find the equation of the parabola in the cases given below:

End points of latus rectum (4, – 8) and (4, 8)

बेरीज

Focus = (4, 0)

Equation of the parabola will be of the form y² = 4ax

Here a = 4

⇒ y² = 16x

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पाठ 5: Two Dimensional Analytical Geometry-II - Exercise 5.2 [पृष्ठ १९६]

पाठ 5 Two Dimensional Analytical Geometry-II
Exercise 5.2 | Q 1. (iv) | पृष्ठ १९६

Find the equation of the parabola whose focus is the point F(-1, -2) and the directrix is the line 4x – 3y + 2 = 0.

Find the co-ordinates of the focus, vertex, equation of the directrix, axis and the length of latus rectum of the parabola

x² = 8y

Find the equation of the parabola which is symmetrical about x-axis and passing through (–2, –3).

The focus of the parabola x² = 16y is:

Find the equation of the ellipse in the cases given below:

Foci `(+- 3, 0), "e"+ 1/2`

Find the equation of the ellipse in the cases given below:

Foci (0, ±4) and end points of major axis are (0, ±5)

Find the equation of the ellipse in the cases given below:

Length of latus rectum 8, eccentricity = `3/5` centre (0, 0) and major axis on x-axis

Find the equation of the hyperbola in the cases given below:

Centre (2, 1), one of the foci (8, 1) and corresponding directrix x = 4