Advertisements
Advertisements
प्रश्न
Find the value of `4/((216)^(-2/3)) + 1/((256)^(- 3/4)) + 2/((243)^(- 1/5))`
उत्तर
`4/((216)^(-2/3)) + 1/((256)^(- 3/4)) + 2/((243)^(- 1/5))`
⇒ `4 xx (216)^(2/3) + (256)^(3/4) + 2 xx (243)^(1/5)`
⇒ `4 xx (6^3)^(2/3) + (4^4)^(3/4) + 2 xx (3^5)^(1/5)`
By law indices (am)n = amn
⇒ 4 × (6)2 + (4)2 + 2 × (3)1
⇒ 4 × 36 + (4)3 + 2 × (3)1
= 144 + 64 + 6
= 214
APPEARS IN
संबंधित प्रश्न
Recall, π is defined as the ratio of the circumference (say c) of a circle to its diameter (say d). That is, π = `c/d`. This seems to contradict the fact that π is irrational. How will you resolve this contradiction?
Simplify the following expressions:
`(4 + sqrt7)(3 + sqrt2)`
Simplify the following expressions:
`(sqrt5 - 2)(sqrt3 - sqrt5)`
Simplify the following expressions:
`(sqrt3 + sqrt7)^2`
Simplify
`1/(2 + sqrt3) + 2/(sqrt5 - sqrt3) + 1/(2 - sqrt5)`
In the following determine rational numbers a and b:
`(sqrt11 - sqrt7)/(sqrt11 + sqrt7) = a - bsqrt77`
Find the value of `6/(sqrt5 - sqrt3)` it being given that `sqrt3 = 1.732` and `sqrt5 = 2.236`
Write the reciprocal of \[5 + \sqrt{2}\].
Simplify the following expression:
`(3+sqrt3)(3-sqrt3)`
Rationalise the denominator of the following:
`(3 + sqrt(2))/(4sqrt(2))`
