Advertisements
Advertisements
प्रश्न
Write the reciprocal of \[5 + \sqrt{2}\].
उत्तर
Given that,`5+sqrt2` it’s reciprocal is given as
`1/(5+sqrt2)`
It can be simplified by rationalizing the denominator. The rationalizing factor of `5+sqrt2` is ` 5 - sqrt2`, we will multiply numerator and denominator of the given expression `1/(5+sqrt2)`by, `5-sqrt2` to get
`1/(5+sqrt2) xx (5-sqrt2)/(5-sqrt2) = (5-sqrt2)/((5)^2 - (sqrt2)^2)`
`= (5-sqrt2) /( 25-2)`
` = (5- sqrt2 ) / 23 `
Hence reciprocal of the given expression is `(5- sqrt2 ) / 23 `.
APPEARS IN
संबंधित प्रश्न
Express the following with rational denominator:
`(sqrt3 + 1)/(2sqrt2 - sqrt3)`
Rationales the denominator and simplify:
`(2sqrt3 - sqrt5)/(2sqrt2 + 3sqrt3)`
Simplify:
`(5 + sqrt3)/(5 - sqrt3) + (5 - sqrt3)/(5 + sqrt3)`
if `x = 2 + sqrt3`,find the value of `x^2 + 1/x^2`
Simplify \[\sqrt{3 + 2\sqrt{2}}\].
Classify the following number as rational or irrational:
2π
After rationalising the denominator of `7/(3sqrt(3) - 2sqrt(2))`, we get the denominator as ______.
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`sqrt(2)/(2 + sqrt(2)`
Simplify:
`64^(-1/3)[64^(1/3) - 64^(2/3)]`
If `a = (3 + sqrt(5))/2`, then find the value of `a^2 + 1/a^2`.