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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

If a d.r.v. X has the following probability distribution: X –2 –1 0 1 2 3 P(X = x) 0.1 k 0.2 2k 0.3 k then P(X = –1) is ______ - Mathematics and Statistics

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प्रश्न

If a d.r.v. X has the following probability distribution:

X –2 –1 0 1 2 3
P(X = x) 0.1 k 0.2 2k 0.3 k

then P(X = –1) is ______

पर्याय

  • `1/10`

  • `2/10`

  • `3/10`

  • `4/10`

MCQ
रिकाम्या जागा भरा

उत्तर

`1/10`

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Probability Distribution of Discrete Random Variables
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2.7: Probability Distributions - MCQ

संबंधित प्रश्‍न

State if the following is not the probability mass function of a random variable. Give reasons for your answer.

X 0 1 2 3 4
P(X) 0.1 0.5 0.2 − 0.1 0.2

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P(Z) 0.3 0.2 0.4 0 0.05

State if the following is not the probability mass function of a random variable. Give reasons for your answer.

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P(Y) 0.6 0.1 0.2

State if the following is not the probability mass function of a random variable. Give reasons for your answer.

0 -1 -2
P(X) 0.3 0.4 0.3

A random variable X has the following probability distribution:

X 0 1 2 3 4 5 6 7
P(X) 0 k 2k 2k 3k k2 2k2 7k2 + k

Determine:

  1. k
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Find expected value and variance of X for the following p.m.f.

x -2 -1 0 1 2
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Let X denote the sum of the numbers obtained when two fair dice are rolled. Find the standard deviation of X.


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If a r.v. X has p.d.f., 

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Choose the correct option from the given alternative:

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Choose the correct option from the given alternative:

Find expected value of and variance of X for the following p.m.f.

X -2 -1 0 1 2
P(x) 0.3 0.3 0.1 0.05 0.25

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X −3 −2 −1 0 1 2 3 4
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Fill in the blank :

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State whether the following is True or False :

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Solve the following problem :

The probability distribution of a discrete r.v. X is as follows.

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Find P(X ≤ 4), P(2 < X < 4), P(X ≤ 3).


Solve the following problem :

Find the expected value and variance of the r. v. X if its probability distribution is as follows.

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Solve the following problem :

Let the p. m. f. of the r. v. X be

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Choose the correct alternative:

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pi 0.2 0.3 0.15 0.25 0.1

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= `square`


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x 1 2 3 4 5 6
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P (X = 0) = 5k2, P(X = 1) = 1 – 4k, P(X = 2) = 1 – 2k and P(X = x) = 0 for any other value of X. Find k.


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