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If adj(A) = [2-42-312-7-202], find A - Mathematics

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प्रश्न

If adj(A) = `[(2, -4, 2),(-3, 12, -7),(-2, 0, 2)]`, find A

बेरीज

उत्तर

adj(A) = `[(2, -4, 2),(-3, 12, -7),(-2, 0, 2)]`

A = `+- 1/sqrt(+"adj A"|)` adj (adj A)

|adj (A)| = 2(24 – 0) + 4(– 6 – 14) + 2(0 + 24)

= 48 – 80 + 48

= 16

adj (adj A) = `[(+|(12, - 7),(0, 2)|, -|(-3, - 7),(-2, 2)|, +|(-3, 12),(-2, 0)|),(-|(-4, 2),(0, 2)|, +|(2, 2),(-2, 2)|, -|(2, -4),(-2, 0)|),(+|(-4, 2),(12, -7)|, -|(2, 2),(-3, -7)|, +|(2, -4),(-3, 12)|)]^"T"`

= `[(+(24 - 0), -(-6 - 14), +(0 + 24)), (-(- 8 - 0), +(4 + 4), -(0 - 8)),(+(28 - 24), -(- 14 + 6), +(24 - 12))]^"T"`

= `[(24, 20, 24),(8, 8, 8),(4, 8, 12)]^"T"`

adj (adj A) = `[(24, 8, 4),(20, 8, 8),(4, 8, 12)]`

= `4[(6, 2, 1),(5, 2, 2),(6, 2, 3)]`

`sqrt(|"adj A"|) = sqrt(16)` = 4

A = `+- (1/4) 4[(6, 2, 1),(5, 2, 2),(6, 2, 3)]`

= `+- [(6, 2, 1),(5, 2, 2),(6, 2, 3)]`

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Inverse of a Non-singular Square Matrix
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पाठ 1: Applications of Matrices and Determinants - Exercise 1.1 [पृष्ठ १६]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 1 Applications of Matrices and Determinants
Exercise 1.1 | Q 8 | पृष्ठ १६

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