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प्रश्न
If (ma + nb): b :: (mc + nd) : d, prove that a, b, c, d are in proportion.
उत्तर
(ma + nb): b :: (mc + nd) : d
⇒ `"ma + nb"/"b" = "mc + nd"/"d"`
⇒ mad + nbd = mbc + nbd
⇒ mad = mbc
⇒ ad = bc
⇒ `a/b = c/d`
Hence a : b :: c : d
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