मराठी

Solve x : 36x+1+6x36x+1-6x = 9 - Mathematics

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प्रश्न

Solve x : `(sqrt(36x + 1) + 6sqrt(x))/(sqrt(36x + 1) -6sqrt(x))` = 9

बेरीज

उत्तर

`(sqrt(36x + 1) + 6sqrt(x))/(sqrt(36x + 1) -6sqrt(x)) = (9)/(1)`

Applying componendo and dividendo,

`(sqrt(36x + 1) + 6sqrt(x) + sqrt(36x + 1) - 6sqrt(x))/(sqrt(36x + 1) + 6sqrt(x) - sqrt(36x - 1) + 6sqrt(x)`

= `(9 + 1)/(9 - 1)`

⇒ `(2sqrt(36x + 1))/(12sqrt(x)) = (10)/(8)`

⇒ `sqrt(36x + 1)/(6sqrt(x)) = (5)/(4)`  ...(Squaring both sides)

`(36x + 1)/(36x) = (25)/(16)`
⇒ 36x x 25 = 16(36x + 1)
⇒ 900x = 576x + 16
⇒ 900x - 576x = 16
⇒ 324 = 16

∴ x = `(16)/(324)`

= `(4)/(81)`.

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पाठ 7: Ratio and Proportion - Exercise 7.3

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