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प्रश्न
If Sin 3A = cos (A – 26°), where 3A is an acute angle, find the value of A =?
उत्तर
Cos 𝜃 = sin (90° - 𝜃)
⇒ Cos (A – 26) = sin (90° −(A− 26°))
⇒ Sin 3A = sin (90° − (A – 26))
Equating angles on both sides
3A = 90° − A + 26°
`4A = 116° A = 116/4 = 29^@`
`∴ A = 29^@`
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