Advertisements
Advertisements
प्रश्न
In a cattle breeding firm, it is prescribed that the food ration for one animal must contain 14, 22, and 1 unit of nutrients A, B, and C respectively. Two different kinds of fodder are available. Each unit weight of these two contains the following amounts of these three nutrients:
Nutrient\Fodder | Fodder 1 | Fodder2 |
Nutrient A | 2 | 1 |
Nutrient B | 2 | 3 |
Nutrient C | 1 | 1 |
The cost of fodder 1 is ₹ 3 per unit and that of fodder ₹ 2 per unit. Formulate the L.P.P. to minimize the cost.
उत्तर
Let x units of fodder 1 and y units of fodder 2 be included in the food ration of an animal.
The cost of fodder 1 is ₹ 3 per unit and that of fodder 2 is ₹ 2 per unit.
∴ Total cost = ₹ (3x + 2y)
The minimum requirement of nutrients A, B, C for an animal are 14, 22 and 1 unit respectively.
We construct the given table with the minimum requirement column as follows:
Nutrient\Fodder | Fodder 1 (x) |
Fodder 2 (y) |
Minimum requirement |
Nutrient A | 2 | 1 | 14 |
Nutrient B | 2 | 3 | 22 |
Nutrient C | 1 | 1 | 1 |
From the table, the food ration of an animal must contain (2x + y) units of nutrient A, (2x + 3y) units of B and (x + y) units of C.
∴ The constraints are :
2x + y ≥ 14
2x + 3y ≥ 22
x + y ≥ 1
Since x and y cannot be negative, we have x ≥ 0, y ≥ 0
∴ The given problem can be formulated as follows:
Minimize Z = 3x + 2y
Subject to 2x + y ≥ 14,
2x + 3y ≥ 22,
x + y ≥ 1,
x ≥ 0,
y ≥ 0.
APPEARS IN
संबंधित प्रश्न
Find the feasible solution of the following inequation:
3x + 2y ≤ 18, 2x + y ≤ 10, x ≥ 0, y ≥ 0
Find the feasible solution of the following inequations:
x - 2y ≤ 2, x + y ≥ 3, - 2x + y ≤ 4, x ≥ 0, y ≥ 0
A manufacturing firm produces two types of gadgets A and B, which are first processed in the foundry and then sent to the machine shop for finishing. The number of man-hours of labour required in each shop for production of A and B per unit and the number of man-hours available for the firm is as follows :
Gadgets | Foundry | Machine shop |
A | 10 | 5 |
B | 6 | 4 |
Time available (hour) | 60 | 35 |
Profit on the sale of A is ₹ 30 and B is ₹ 20 per units. Formulate the L.P.P. to have maximum profit.
A company manufactures two types of chemicals Aand B. Each chemical requires two types of raw material P and Q. The table below shows number of units of P and Q required to manufacture one unit of A and one unit of B and the total availability of P and Q.
Chemical→ | A | B | Availability |
Raw Material ↓ | |||
P | 3 | 2 | 120 |
Q | 2 | 5 | 160 |
The company gets profits of ₹ 350 and ₹ 400 by selling one unit of A and one unit of B respectively. (Assume that the entire production of A and B can be sold). How many units of the chemicals A and B should be manufactured so that the company gets a maximum profit? Formulate the problem as LPP to maximize profit.
A company manufactures two types of fertilizers F1 and F2. Each type of fertilizer requires two raw materials A and B. The number of units of A and B required to manufacture one unit of fertilizer F1 and F2 and availability of the raw materials A and B per day are given in the table below:
Fertilizers→ | F1 | F2 | Availability |
Raw Material ↓ | |||
A | 2 | 3 | 40 |
B | 1 | 4 | 70 |
By selling one unit of F1 and one unit of F2, the company gets a profit of ₹ 500 and ₹ 750 respectively. Formulate the problem as LPP to maximize the profit.
If John drives a car at a speed of 60 km/hour, he has to spend ₹ 5 per km on petrol. If he drives at a faster speed of 90 km/hour, the cost of petrol increases ₹ 8 per km. He has ₹ 600 to spend on petrol and wishes to travel the maximum distance within an hour. Formulate the above problem as L.P.P.
Solve the following LPP by graphical method:
Maximize z = 11x + 8y, subject to x ≤ 4, y ≤ 6, x + y ≤ 6, x ≥ 0, y ≥ 0
Objective function of LPP is ______.
The maximum value of z = 10x + 6y subject to the constraints 3x + y ≤ 12, 2x + 5y ≤ 34, x, ≥ 0, y ≥ 0 is ______.
If the corner points of the feasible solution are (0, 0), (3, 0), (2, 1), `(0, 7/3)` the maximum value of z = 4x + 5y is ______.
Solve the following LPP:
Maximize z = 5x1 + 6x2 subject to 2x1 + 3x2 ≤ 18, 2x1 + x2 ≤ 12, x1 ≥ 0, x2 ≥ 0.
Solve the following LPP:
Maximize z = 4x + 2y subject to 3x + y ≤ 27, x + y ≤ 21, x ≥ 0, y ≥ 0.
Solve each of the following inequations graphically using XY-plane:
4x - 18 ≥ 0
Sketch the graph of the following inequation in XOY co-ordinate system:
|x + 5| ≤ y
Solve the following LPP:
Maximize z =60x + 50y subject to
x + 2y ≤ 40, 3x + 2y ≤ 60, x ≥ 0, y ≥ 0.
A carpenter makes chairs and tables. Profits are ₹ 140 per chair and ₹ 210 per table. Both products are processed on three machines: Assembling, Finishing and Polishing. The time required for each product in hours and availability of each machine is given by the following table:
Product → | Chair (x) | Table (y) | Available time (hours) |
Machine ↓ | |||
Assembling | 3 | 3 | 36 |
Finishing | 5 | 2 | 50 |
Polishing | 2 | 6 | 60 |
Formulate the above problem as LPP. Solve it graphically
A chemical company produces a chemical containing three basic elements A, B, C, so that it has at least 16 litres of A, 24 litres of B and 18 litres of C. This chemical is made by mixing two compounds I and II. Each unit of compound I has 4 litres of A, 12 litres of B and 2 litres of C. Each unit of compound II has 2 litres of A, 2 litres of B and 6 litres of C. The cost per unit of compound I is ₹ 800 and that of compound II is ₹ 640. Formulate the problems as LPP and solve it to minimize the cost.
Objective function of LPP is ______.
Choose the correct alternative :
Solution of LPP to minimize z = 2x + 3y st. x ≥ 0, y ≥ 0, 1≤ x + 2y ≤ 10 is
State whether the following is True or False :
The feasible solution of LPP belongs to only quadrant I.
The point of which the maximum value of z = x + y subject to constraints x + 2y ≤ 70, 2x + y ≤ 90, x ≥ 0, y ≥ 0 is obtained at
Maximize z = 5x + 2y subject to 3x + 5y ≤ 15, 5x + 2y ≤ 10, x ≥ 0, y ≥ 0
Minimize z = 7x + y subjected to 5x + y ≥ 5, x + y ≥ 3, x ≥ 0, y ≥ 0
A company produces two types of products say type A and B. Profits on the two types of product are ₹ 30/- and ₹ 40/- per kg respectively. The data on resources required and availability of resources are given below.
Requirements | Capacity available per month | ||
Product A | Product B | ||
Raw material (kgs) | 60 | 120 | 12000 |
Machining hours/piece | 8 | 5 | 600 |
Assembling (man hours) | 3 | 4 | 500 |
Formulate this problem as a linear programming problem to maximize the profit.
Maximize: z = 3x1 + 4x2 subject to 2x1 + x2 ≤ 40, 2x1 + 5x2 ≤ 180, x1, x2 ≥ 0. In the LPP, which one of the following is feasible comer point?
Solve the following linear programming problem graphically.
Maximise Z = 4x1 + x2 subject to the constraints x1 + x2 ≤ 50; 3x1 + x2 ≤ 90 and x1 ≥ 0, x2 ≥ 0.
Solve the following problems by graphical method:
Maximize z = 4x + 2y subject to 3x + y ≥ 27, x + y ≥ 21, x ≥ 0 y ≥ 0
Sketch the graph of the following inequation in XOY co-ordinate system.
2y - 5x ≥ 0