मराठी

In ΔABC, AB = AC. D is a point in the interior of the triangle such that ∠DBC = ∠DCB. Prove that AD bisects ∠BAC of ΔABC. - Mathematics

Advertisements
Advertisements

प्रश्न

In ΔABC, AB = AC. D is a point in the interior of the triangle such that ∠DBC = ∠DCB. Prove that AD bisects ∠BAC of ΔABC.

बेरीज

उत्तर

Since AB = AC

∠ABC = ∠ACB

But ∠DBC = ∠DBC

⇒ ∠ABD = ∠ACD

Now in ΔABD and ΔADC

AB = AC

AD = AD

∠ABD = ∠ACD

Therefore, ΔABD ≅ ΔADC  ...(SSA criteria)

Hence, ∠BAD = ∠CAD

Thus, AD bisects ∠BAC.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 11: Triangles and their congruency - Exercise 11.2

APPEARS IN

फ्रँक Mathematics [English] Class 9 ICSE
पाठ 11 Triangles and their congruency
Exercise 11.2 | Q 25
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×