Advertisements
Advertisements
प्रश्न
In the figure given below, PT is a tangent to the circle. Find PT if AT = 16 cm and AB = 12 cm.
उत्तर
PT is tangent.
Hence by theorem,
PT2 = AT x BT
PT2 = 16 x (AT - AB)
PT2 = 16 x (16 - 12)
PT2 = 16 x 4 = 64
PT = 8 cm.
APPEARS IN
संबंधित प्रश्न
From a point Q, 13 cm away from the centre of a circle, the length of tangent PQ to the circle is 12 cm. The radius of the circle (in cm) is
Four alternative answers for the following question is given. Choose the correct alternative.
If two circles are touching externally, how many common tangents of them can be drawn?
A chord PQ of a circle is parallel to the tangent drawn at a point R of the circle. Prove that R bisects the arc PRQ.
PA and PB are tangents from P to the circle with centre O. At M, a tangent is drawn cutting PA at K and PB at N. Prove that KN = AK + BN.
In Fig. the incircle of ΔABC touches the sides BC, CA, and AB at D, E respectively. Show that: AF + BD + CE = AE + BF + CD = `1/2`( Perimeter of ΔABC)
In figure, M is the centre of the circle and seg KL is a tangent segment. If MK = 12, KL = `6sqrt(3)`, then find
(i) Radius of the circle.
(ii) Measures of ∠K and ∠M.
In figure, if ∠AOB = 125°, then ∠COD is equal to ______.
Prove that the tangents drawn at the ends of a chord of a circle make equal angles with the chord.
ΔABC circumscribes a circle of radius r such that ∠B = 90°. If AB = 3 cm and BC = 4 cm, then find the value of r.
In the given figure, O is the centre of the circle. PQ is a tangent to the circle at T. Chord AB produced meets the tangent at P.
AB = 9 cm, BP = 16 cm, ∠PTB = 50° ∠OBA = 45°
Find:
- Length of PT
- ∠BAT
- ∠BOT
- ∠ABT