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प्रश्न
One branch of cos–1 other than the principal value branch corresponds to ______.
पर्याय
`[pi/2, (3pi)/2]`
`[pi, 2pi]- {(3pi)/2}`
(0, π)
[2π, 3π]
उत्तर
One branch of cos–1 other than the principal value branch corresponds to [2π, 3π].
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संबंधित प्रश्न
The principal solution of `cos^-1(-1/2)` is :
Find the principal value of the following:
`sin^-1((sqrt3-1)/(2sqrt2))`
Find the principal value of the following:
`sin^-1(tan (5pi)/4)`
For the principal value, evaluate of the following:
`cos^-1 1/2+2sin^-1 (1/2)`
For the principal value, evaluate of the following:
`sin^-1(-1/2)+2cos^-1(-sqrt3/2)`
Find the principal value of the following:
`tan^-1(cos pi/2)`
Find the principal value of the following:
`sec^-1(2)`
Find the principal value of the following:
cosec-1(-2)
Find the principal value of the following:
`\text(cosec)^-1(2/sqrt3)`
Find the principal value of the following:
`cosec^-1(2cos (2pi)/3)`
For the principal value, evaluate the following:
`sin^-1(-sqrt3/2)+\text{cosec}^-1(-2/sqrt3)`
For the principal value, evaluate the following:
`sin^-1[cos{2\text(cosec)^-1(-2)}]`
Show that `"sin"^-1(5/13) + "cos"^-1(3/5) = "tan"^-1(63/16)`
Find the value of `sin(2tan^-1 2/3) + cos(tan^-1 sqrt(3))`
The principal value branch of sec–1 is ______.
The principal value of `sin^-1 ((-sqrt(3))/2)` is ______.
Find the value of `tan^-1 (tan (5pi)/6) +cos^-1(cos (13pi)/6)`
If `cos(sin^-1 2/5 + cos^-1x)` = 0, then x is equal to ______.
The principal value of `cos^-1 (- 1/2)` is ______.
The value of `sin^-1 (sin (3pi)/5)` is ______.
The value of expression `tan((sin^-1x + cos^-1x)/2)`, when x = `sqrt(3)/2` is ______.
The value of the expression (cos–1x)2 is equal to sec2x.
The minimum value of n for which `tan^-1 "n"/pi > pi/4`, n ∈ N, is valid is 5.
The principal value of `sin^-1 [cos(sin^-1 1/2)]` is `pi/3`.
If sin `("sin"^-1 1/5 + "cos"^-1 "x") = 1,` then the value of x is ____________.
If `"tan"^-1 "x" + "tan"^-1"y + tan"^-1 "z" = pi/2, "x,y,x" > 0,` then the value of xy+yz+zx is ____________.
What is the principal value of `cot^-1 ((-1)/sqrt(3))`?
Assertion (A): Maximum value of (cos–1 x)2 is π2.
Reason (R): Range of the principal value branch of cos–1 x is `[(-π)/2, π/2]`.
