Advertisements
Advertisements
प्रश्न
One branch of cos–1 other than the principal value branch corresponds to ______.
विकल्प
`[pi/2, (3pi)/2]`
`[pi, 2pi]- {(3pi)/2}`
(0, π)
[2π, 3π]
उत्तर
One branch of cos–1 other than the principal value branch corresponds to [2π, 3π].
APPEARS IN
संबंधित प्रश्न
Write the principal value of `tan^(-1)+cos^(-1)(-1/2)`
Prove that `sin^(-1) (3/5) + cos^(-1) (12/13) = sin^(-1) (56/65)`
Find the value of `tan^(-1) sqrt3 - cot^(-1) (-sqrt3)`
Find the principal value of the following:
`sin^-1((sqrt3-1)/(2sqrt2))`
Find the principal value of the following:
`sec^-1(-sqrt2)`
Find the principal value of the following:
`sec^-1(2)`
Find the principal value of the following:
`cosec^-1(-sqrt2)`
For the principal value, evaluate the following:
`sin^-1[cos{2\text(cosec)^-1(-2)}]`
Show that `"sin"^-1(5/13) + "cos"^-1(3/5) = "tan"^-1(63/16)`
Solve for x, if:
tan (cos-1x) = `2/sqrt5`
Find the value of `sec(tan^-1 y/2)`
Find value of tan (cos–1x) and hence evaluate `tan(cos^-1 8/17)`
Find the value of `sin(2tan^-1 2/3) + cos(tan^-1 sqrt(3))`
The value of cot (sin–1x) is ______.
The domain of sin–1 2x is ______.
If sin–1x + sin–1y = `pi/2`, then value of cos–1x + cos–1y is ______.
The value of `tan(cos^-1 3/5 + tan^-1 1/4)` is ______.
The domain of the function defined by f(x) = `sin^-1 sqrt(x- 1)` is ______.
If `cos(sin^-1 2/5 + cos^-1x)` = 0, then x is equal to ______.
The value of `cot[cos^-1 (7/25)]` is ______.
The set of values of `sec^-1 (1/2)` is ______.
The value of cos (sin–1x + cos–1x), |x| ≤ 1 is ______.
The value of expression `tan((sin^-1x + cos^-1x)/2)`, when x = `sqrt(3)/2` is ______.
The principal value of `sin^-1 [cos(sin^-1 1/2)]` is `pi/3`.
If `5 sin theta = 3 "then", (sec theta + tan theta)/(sec theta - tan theta)` is equal to ____________.
If sin `("sin"^-1 1/5 + "cos"^-1 "x") = 1,` then the value of x is ____________.
`"sec" {"tan"^-1 (-"y"/3)}` is equal to ____________.
What is the principal value of `cot^-1 ((-1)/sqrt(3))`?
Evaluate `sin^-1 (sin (3π)/4) + cos^-1 (cos π) + tan^-1 (1)`.