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प्रश्न
Find the value of `tan^(-1) sqrt3 - cot^(-1) (-sqrt3)`
उत्तर
`tan^(-1) (sqrt3) -cot^(-1) (-sqrt3)`
`= tan^(-1) {tan (pi/3)} - cot^(-1) (cot (5pi)/6)` [∵ Range of `tan^(-1) is (-pi/2, pi/2); pi/3 in (-pi/2, pi/2)`
and range of `cot^(-1) is [0, pi]; (5pi)/6 in [0,pi]]`
`= pi/3 - (5pi)/6`
`= -pi/2`
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