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प्रश्न
The domain of sin–1 2x is ______.
विकल्प
[0, 1]
[– 1, 1]
`[-1/2, 1/2]`
[–2, 2]
उत्तर
The domain of sin–1 2x is `[-1/2, 1/2]`.
Explanation:
Let sin–12x = θ
So that 2x = sin θ.
Now – 1 ≤ sin θ ≤ 1
i.e.,– 1 ≤ 2x ≤ 1
Which gives `-1/2 ≤ x ≤ 1/2`.
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