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Find the values of x which satisfy the equation sin–1x + sin–1(1 – x) = cos–1x. - Mathematics

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प्रश्न

Find the values of x which satisfy the equation sin–1x + sin–1(1 – x) = cos–1x.

योग

उत्तर

From the given equation

We have sin (sin–1x + sin–1 (1 – x)) = sin (cos–1x)

⇒ sin (sin–1x) cos (sin–1(1 – x)) + cos (sin–1x) sin (sin–1(1 – x) ) = sin (cos–1x)

⇒ `xsqrt(1 - (1 - x)^2) + (1 - x) sqrt(1 - x^2) = sqrt(1 - x^2)`

⇒ `xsqrt(2x - x^2) + sqrt(1 - x^2) (1 - x - 1)` = 0

⇒ `x(sqrt(2x - x^2) - sqrt(1 - x^2))` = 0

⇒ x = 0 or `2x - x^2 = 1 - x^2`

⇒ x = 0 or x =`1/2`.

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अध्याय 2: Inverse Trigonometric Functions - Solved Examples [पृष्ठ २६]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 2 Inverse Trigonometric Functions
Solved Examples | Q 18 | पृष्ठ २६

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