For the principal value, evaluate the following: `sec^-1(sqrt2)+2\text{cosec}^-1(-sqrt2)`

`sec^-1(sqrt2)+2cosec^-1(-sqrt2)=sec^-1(sec pi/4)+2cosec^-1[cosec(-pi/4)]` `=pi/4-2xxpi/4` `=pi/4-pi/2` `=-pi/4`

For the Principal Value, Evaluate the Following: `Sec^-1(Sqrt2)+2cosec^-1(-sqrt2)` - Mathematics

प्रश्न

For the principal value, evaluate the following:

$\sec^{- 1} (\sqrt{2}) + 2 {cosec}^{- 1} (- \sqrt{2})$

संक्षेप में उत्तर

उत्तर

$\sec^{- 1} (\sqrt{2}) + 2 \cos e c^{- 1} (- \sqrt{2}) = \sec^{- 1} (\sec \frac{π}{4}) + 2 \cos e c^{- 1} [\cos e c (- \frac{π}{4})]$

$= \frac{π}{4} - 2 \times \frac{π}{4}$

$= \frac{π}{4} - \frac{π}{2}$

$= - \frac{π}{4}$

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Inverse Trigonometric Functions - Inverse Trigonometric Functions - Principal Value Branch

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Q 3.2 Q 3.1 Q 3.3

अध्याय 4: Inverse Trigonometric Functions - Exercise 4.05 [पृष्ठ २१]

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अध्याय 4 Inverse Trigonometric Functions
Exercise 4.05 | Q 3.2 | पृष्ठ २१

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For the Principal Value, Evaluate the Following: Sec-1(Sqrt2)+2cosec-1(-2) - Mathematics

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For the Principal Value, Evaluate the Following: ${Sec}^{- 1} (S q r t 2) + 2 \cos e c^{- 1} (- \sqrt{2})$ - Mathematics

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