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प्रश्न
The domain of trigonometric functions can be restricted to any one of their branch (not necessarily principal value) in order to obtain their inverse functions.
विकल्प
True
False
उत्तर
This statement is True.
Explanation:
We know that all trigonometric functions are restricted over their domains to obtain their inverse functions.
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संबंधित प्रश्न
The principal solution of `cos^-1(-1/2)` is :
Write the principal value of `tan^(-1)+cos^(-1)(-1/2)`
Find the principal value of the following:
`sin^-1(-sqrt3/2)`
For the principal value, evaluate of the following:
`sin^-1(-sqrt3/2)+cos^-1(sqrt3/2)`
Find the principal value of the following:
`sec^-1(2tan (3pi)/4)`
For the principal value, evaluate the following:
`sin^-1(-sqrt3/2)+\text{cosec}^-1(-2/sqrt3)`
Find the principal value of cos–1x, for x = `sqrt(3)/2`.
Find the value of `cos^-1(cos (13pi)/6)`.
Find value of tan (cos–1x) and hence evaluate `tan(cos^-1 8/17)`
The principal value branch of sec–1 is ______.
The principal value of the expression cos–1[cos (– 680°)] is ______.
The principal value of `sin^-1 ((-sqrt(3))/2)` is ______.
Let θ = sin–1 (sin (– 600°), then value of θ is ______.
The value of sin (2 sin–1 (.6)) is ______.
The value of the expression sin [cot–1 (cos (tan–11))] is ______.
Find the value of `tan^-1 (tan (5pi)/6) +cos^-1(cos (13pi)/6)`
Find the value of `4tan^-1 1/5 - tan^-1 1/239`
The domain of the function cos–1(2x – 1) is ______.
The value of `cot[cos^-1 (7/25)]` is ______.
The value of `cos^-1 (cos (14pi)/3)` is ______.
The value of the expression (cos–1x)2 is equal to sec2x.
The minimum value of n for which `tan^-1 "n"/pi > pi/4`, n ∈ N, is valid is 5.
If sin `("sin"^-1 1/5 + "cos"^-1 "x") = 1,` then the value of x is ____________.
`"cos" ["tan"^-1 {"sin" ("cot"^-1 "x")}]` is equal to ____________.
Which of the following is the principal value branch of `"cos"^-1 "x"`
What is the principal value of `cot^-1 ((-1)/sqrt(3))`?
Assertion (A): Maximum value of (cos–1 x)2 is π2.
Reason (R): Range of the principal value branch of cos–1 x is `[(-π)/2, π/2]`.
