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Prove that the function f(x) = tanx – 4x is strictly decreasing on (-π3,π3) - Mathematics

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प्रश्न

Prove that the function f(x) = tanx – 4x is strictly decreasing on `((-pi)/3, pi/3)`

बेरीज

उत्तर

f(x) = tan x – 4x

⇒ f'(x) = sec2x – 4

When `(-pi)/4 < x < pi/3, 1 < secx < 2`

Therefore, 1 < sec2x < 4

⇒ 3 < (sec2x – 4) < 0

Thus for `(-pi)/4 < x < pi/3`, f'(x) < 0

Hence f is strictly decreasing on `((-pi)/3, pi/3)`.

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पाठ 6: Application Of Derivatives - Solved Examples [पृष्ठ १२१]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
पाठ 6 Application Of Derivatives
Solved Examples | Q 4 | पृष्ठ १२१

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