Advertisements
Advertisements
प्रश्न
Solve the equation x2 + 3 = 0
उत्तर
The given quadratic equation is x2 + 3 = 0
On comparing the given equation with ax2 + bx + c = 0, we obtain
a = 1, b = 0, and c = 3
Therefore, the discriminant of the given equation is
D = b2 – 4ac = 02 – 4 × 1 × 3 = –12
Therefore, the required solutions are
APPEARS IN
संबंधित प्रश्न
Solve the equation 2x2 + x + 1 = 0
Solve the equation x2 + 3x + 9 = 0
Solve the equation x2 + 3x + 5 = 0
Solve the equation x2 – x + 2 = 0
Solve the equation `x^2 + x + 1/sqrt2 = 0`
Solve the equation `x^2 + x/sqrt2 + 1 = 0`
For any two complex numbers z1 and z2, prove that Re (z1z2) = Re z1 Re z2 – Imz1 Imz2
Solve the equation `x^2 -2x + 3/2 = 0`
9x2 + 4 = 0
4x2 − 12x + 25 = 0
x2 + x + 1 = 0
\[4 x^2 + 1 = 0\]
\[x^2 - x + 1 = 0\]
\[17 x^2 - 8x + 1 = 0\]
\[21 x^2 - 28x + 10 = 0\]
\[13 x^2 + 7x + 1 = 0\]
\[\sqrt{3} x^2 - \sqrt{2}x + 3\sqrt{3} = 0\]
\[x^2 + \frac{x}{\sqrt{2}} + 1 = 0\]
\[\sqrt{5} x^2 + x + \sqrt{5} = 0\]
\[- x^2 + x - 2 = 0\]
Solving the following quadratic equation by factorization method:
\[x^2 + 10ix - 21 = 0\]
Solve the following quadratic equation:
\[\left( 2 + i \right) x^2 - \left( 5 - i \right) x + 2 \left( 1 - i \right) = 0\]
Solve the following quadratic equation:
\[x^2 + 4ix - 4 = 0\]
Solve the following quadratic equation:
\[i x^2 - x + 12i = 0\]
Write the number of real roots of the equation \[(x - 1 )^2 + (x - 2 )^2 + (x - 3 )^2 = 0\].
If a and b are roots of the equation \[x^2 - px + q = 0\], than write the value of \[\frac{1}{a} + \frac{1}{b}\].
If a and b are roots of the equation \[x^2 - x + 1 = 0\], then write the value of a2 + b2.
If α, β are the roots of the equation \[a x^2 + bx + c = 0, \text { then } \frac{1}{a\alpha + b} + \frac{1}{a\beta + b} =\]
The values of k for which the quadratic equation \[k x^2 + 1 = kx + 3x - 11 x^2\] has real and equal roots are
If the equations \[x^2 + 2x + 3\lambda = 0 \text { and } 2 x^2 + 3x + 5\lambda = 0\] have a non-zero common roots, then λ =
The number of roots of the equation \[\frac{(x + 2)(x - 5)}{(x - 3)(x + 6)} = \frac{x - 2}{x + 4}\] is
If α and β are the roots of \[4 x^2 + 3x + 7 = 0\], then the value of \[\frac{1}{\alpha} + \frac{1}{\beta}\] is
If α, β are the roots of the equation \[x^2 + px + q = 0 \text { then } - \frac{1}{\alpha} + \frac{1}{\beta}\] are the roots of the equation
Find the value of a such that the sum of the squares of the roots of the equation x2 – (a – 2)x – (a + 1) = 0 is least.
