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प्रश्न
\[- x^2 + x - 2 = 0\]
उत्तर
\[- x^2 + x - 2 = 0\]
\[ \Rightarrow x^2 - x + 2 = 0\]
\[ \Rightarrow x^2 - x + \frac{1}{4} + \frac{7}{4} = 0\]
\[ \Rightarrow x^2 - 2 \times x \times \frac{1}{2} + \left( \frac{1}{2} \right)^2 - \frac{7}{4} i^2 = 0\]
\[ \Rightarrow \left( x - \frac{1}{2} \right)^2 - \left( \frac{i\sqrt{7}}{2} \right)^2 = 0\]
\[ \Rightarrow \left( x - \frac{1}{2} + \frac{i\sqrt{7}}{2} \right) \left( x - \frac{1}{2} - \frac{i\sqrt{7}}{2} \right) = 0\]
\[\Rightarrow \left( x - \frac{1}{2} + \frac{\sqrt{7}}{2}i \right) = 0\] or, \[\left( x - \frac{1}{2} - \frac{\sqrt{7}}{2}i \right) = 0\]
\[\Rightarrow x = \frac{1}{2} - \frac{\sqrt{7}}{2}i\] or, \[x = \frac{1}{2} + \frac{\sqrt{7}}{2}i\]
Hence, the roots of the equation are
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