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Solve the Following Quadratic Equation: X 2 − ( 5 − I ) X + ( 18 + I ) = 0 - Mathematics

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प्रश्न

Solve the following quadratic equation:

\[x^2 - \left( 5 - i \right) x + \left( 18 + i \right) = 0\]

उत्तर

\[ x^2 - \left( 5 - i \right)x + \left( 18 + i \right) = 0\]

\[\text { Comparing the given equation with the general form } a x^2 + bx + c = 0, \text { we get }\]

\[a = 1, b = - \left( 5 - i \right) \text { and } c = \left( 18 + i \right)\]

\[x = \frac{- b \pm \sqrt{b^2 - 4ac}}{2a}\]

\[ \Rightarrow x = \frac{\left( 5 - i \right) \pm \sqrt{\left( 5 - i \right)^2 - 4\left( 18 + i \right)}}{2}\]

\[ \Rightarrow x = \frac{\left( 5 - i \right) \pm \sqrt{\left( 5 - i \right)^2 - 4\left( 18 + i \right)}}{2}\]

\[ \Rightarrow x = \frac{\left( 5 - i \right) \pm \sqrt{- 48 - 14i}}{2}\]

\[ \Rightarrow x = \frac{\left( 5 - i \right) \pm i\sqrt{48 + 14i}}{2}\]

\[ \Rightarrow x = \frac{\left( 5 - i \right) \pm i\sqrt{49 - 1 + 2 \times 7 \times i}}{2}\]

\[ \Rightarrow x = \frac{\left( 5 - i \right) \pm i\sqrt{\left( 7 + i \right)^2}}{2}\]

\[ \Rightarrow x = \frac{\left( 5 - i \right) \pm i\left( 7 + i \right)}{2}\]

\[ \Rightarrow x = \frac{\left( 5 - i \right) + i\left( 7 + i \right)}{2} \text { or }x = \frac{\left( 5 - i \right) - i\left( 7 + i \right)}{2}\]

\[ \Rightarrow x = 2 + 3i, 3 - 4i\]

\[\text { So, the roots of the given quadratic equation are } 2 + 3i \text { and } 3 - 4i .\]

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पाठ 14: Quadratic Equations - Exercise 14.2 [पृष्ठ १३]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 14 Quadratic Equations
Exercise 14.2 | Q 2.02 | पृष्ठ १३

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