Advertisements
Advertisements
प्रश्न
\[x^2 + 2x + 5 = 0\]
उत्तर
We have:
\[x^2 + 2x + 2 = 0\]
\[ \Rightarrow x^2 + 2x + 1 + 1 = 0\]
\[ \Rightarrow x^2 + 2 \times x \times 1 + 1^2 - (i )^2 = 0\]
\[ \Rightarrow (x + 1 )^2 - (i )^2 = 0\]
\[ \Rightarrow (x + 1 + i) (x + 1 - i) = 0\]
\[\Rightarrow (x + 1 + i) = 0\] or \[(x + 1 - i) = 0\]
\[\Rightarrow x = - 1 - i\] or \[x = - 1 + i\]
Hence, the roots of the equation are
APPEARS IN
संबंधित प्रश्न
Solve the equation 2x2 + x + 1 = 0
Solve the equation `x^2 + x/sqrt2 + 1 = 0`
Solve the equation `3x^2 - 4x + 20/3 = 0`
Solve the equation `x^2 -2x + 3/2 = 0`
Solve the equation 27x2 – 10x + 1 = 0
Solve the equation 21x2 – 28x + 10 = 0
x2 + 1 = 0
\[4 x^2 + 1 = 0\]
\[x^2 + x + 1 = 0\]
\[27 x^2 - 10 + 1 = 0\]
\[17 x^2 + 28x + 12 = 0\]
\[2 x^2 + x + 1 = 0\]
\[\sqrt{2} x^2 + x + \sqrt{2} = 0\]
\[3 x^2 - 4x + \frac{20}{3} = 0\]
Solve the following quadratic equation:
\[x^2 - \left( 2 + i \right) x - \left( 1 - 7i \right) = 0\]
Solve the following quadratic equation:
\[x^2 + 4ix - 4 = 0\]
Solve the following quadratic equation:
\[2 x^2 + \sqrt{15}ix - i = 0\]
Solve the following quadratic equation:
\[i x^2 - x + 12i = 0\]
Solve the following quadratic equation:
\[x^2 - \left( 3\sqrt{2} - 2i \right) x - \sqrt{2} i = 0\]
Solve the following quadratic equation:
\[2 x^2 - \left( 3 + 7i \right) x + \left( 9i - 3 \right) = 0\]
If a and b are roots of the equation \[x^2 - x + 1 = 0\], then write the value of a2 + b2.
If α, β are roots of the equation \[x^2 + lx + m = 0\] , write an equation whose roots are \[- \frac{1}{\alpha}\text { and } - \frac{1}{\beta}\].
For the equation \[\left| x \right|^2 + \left| x \right| - 6 = 0\] ,the sum of the real roots is
If a, b are the roots of the equation \[x^2 + x + 1 = 0, \text { then } a^2 + b^2 =\]
The values of x satisfying log3 \[( x^2 + 4x + 12) = 2\] are
The number of real roots of the equation \[( x^2 + 2x )^2 - (x + 1 )^2 - 55 = 0\] is
If α, β are the roots of the equation \[a x^2 + bx + c = 0, \text { then } \frac{1}{a\alpha + b} + \frac{1}{a\beta + b} =\]
If α, β are the roots of the equation \[x^2 + px + 1 = 0; \gamma, \delta\] the roots of the equation \[x^2 + qx + 1 = 0, \text { then } (\alpha - \gamma)(\alpha + \delta)(\beta - \gamma)(\beta + \delta) =\]
If one root of the equation \[x^2 + px + 12 = 0\] while the equation \[x^2 + px + q = 0\] has equal roots, the value of q is
The number of roots of the equation \[\frac{(x + 2)(x - 5)}{(x - 3)(x + 6)} = \frac{x - 2}{x + 4}\] is
If α, β are the roots of the equation \[x^2 + px + q = 0 \text { then } - \frac{1}{\alpha} + \frac{1}{\beta}\] are the roots of the equation
If α, β are the roots of the equation \[x^2 - p(x + 1) - c = 0, \text { then } (\alpha + 1)(\beta + 1) =\]
Find the value of P such that the difference of the roots of the equation x2 – Px + 8 = 0 is 2.