Advertisements
Advertisements
प्रश्न
If a, b are the roots of the equation \[x^2 + x + 1 = 0, \text { then } a^2 + b^2 =\]
पर्याय
1
2
-1
3
उत्तर
−1
Given equation:
\[x^2 + x + 1 = 0\]
Also,
\[a\] and \[b\] are the roots of the given equation.
Sum of the roots = \[a + b = \frac{- \text { Coefficient of }x}{\text { Coefficient of } x^2} = - \frac{1}{1} = - 1\]
Product of the roots = \[ab = \frac{\text { Constant term }}{\text { Coefficient of } x^2} = \frac{1}{1} = 1\]
\[\therefore (a + b )^2 = a^2 + b^2 + 2ab\]
\[ \Rightarrow ( - 1 )^2 = a^2 + b^2 + 2 \times 1\]
\[ \Rightarrow 1 - 2 = a^2 + b^2 \]
\[ \Rightarrow a^2 + b^2 = - 1\]
APPEARS IN
संबंधित प्रश्न
Solve the equation x2 + 3x + 9 = 0
Solve the equation –x2 + x – 2 = 0
Solve the equation `x^2 + x + 1/sqrt2 = 0`
For any two complex numbers z1 and z2, prove that Re (z1z2) = Re z1 Re z2 – Imz1 Imz2
Solve the equation `3x^2 - 4x + 20/3 = 0`
x2 + 1 = 0
9x2 + 4 = 0
\[4 x^2 + 1 = 0\]
\[27 x^2 - 10 + 1 = 0\]
\[8 x^2 - 9x + 3 = 0\]
\[13 x^2 + 7x + 1 = 0\]
\[\sqrt{3} x^2 - \sqrt{2}x + 3\sqrt{3} = 0\]
\[x^2 + x + \frac{1}{\sqrt{2}} = 0\]
\[x^2 + \frac{x}{\sqrt{2}} + 1 = 0\]
\[- x^2 + x - 2 = 0\]
\[3 x^2 - 4x + \frac{20}{3} = 0\]
Solving the following quadratic equation by factorization method:
\[x^2 - \left( 2\sqrt{3} + 3i \right) x + 6\sqrt{3}i = 0\]
Solve the following quadratic equation:
\[x^2 - \left( 5 - i \right) x + \left( 18 + i \right) = 0\]
Solve the following quadratic equation:
\[x^2 - \left( 2 + i \right) x - \left( 1 - 7i \right) = 0\]
Solve the following quadratic equation:
\[i x^2 - 4 x - 4i = 0\]
Solve the following quadratic equation:
\[2 x^2 + \sqrt{15}ix - i = 0\]
Solve the following quadratic equation:
\[x^2 - x + \left( 1 + i \right) = 0\]
Solve the following quadratic equation:
\[x^2 - \left( 3\sqrt{2} - 2i \right) x - \sqrt{2} i = 0\]
Write the number of real roots of the equation \[(x - 1 )^2 + (x - 2 )^2 + (x - 3 )^2 = 0\].
If roots α, β of the equation \[x^2 - px + 16 = 0\] satisfy the relation α2 + β2 = 9, then write the value P.
If \[2 + \sqrt{3}\] is root of the equation \[x^2 + px + q = 0\] than write the values of p and q.
If the difference between the roots of the equation \[x^2 + ax + 8 = 0\] is 2, write the values of a.
If a and b are roots of the equation \[x^2 - x + 1 = 0\], then write the value of a2 + b2.
The number of real roots of the equation \[( x^2 + 2x )^2 - (x + 1 )^2 - 55 = 0\] is
If α, β are the roots of the equation \[a x^2 + bx + c = 0, \text { then } \frac{1}{a\alpha + b} + \frac{1}{a\beta + b} =\]
If α, β are the roots of the equation \[x^2 + px + 1 = 0; \gamma, \delta\] the roots of the equation \[x^2 + qx + 1 = 0, \text { then } (\alpha - \gamma)(\alpha + \delta)(\beta - \gamma)(\beta + \delta) =\]
If the roots of \[x^2 - bx + c = 0\] are two consecutive integers, then b2 − 4 c is
Find the value of a such that the sum of the squares of the roots of the equation x2 – (a – 2)x – (a + 1) = 0 is least.