Advertisements
Advertisements
प्रश्न
If roots α, β of the equation \[x^2 - px + 16 = 0\] satisfy the relation α2 + β2 = 9, then write the value P.
उत्तर
Given equation: \[x^2 - px + 16 = 0\]
Also,
\[\alpha\] and \[\beta\] are the roots of the equation satisfying \[\alpha^2 + \beta^2 = 9 .\]
From the equation, we have:
Sum of the roots = \[\alpha + \beta =\]\[- \left( \frac{- p}{1} \right) = p\]
Product of the roots = \[\alpha\beta\] = \[\frac{16}{1} = 16\]
\[\text { Now }, \left( \alpha + \beta \right)^2 = \alpha^2 + \beta^2 + 2\alpha\beta\]
\[ \Rightarrow p^2 = 9 + 32\]
\[ \Rightarrow p^2 = 41\]
\[ \Rightarrow p = \sqrt{41}\]
Hence, the value of \[p \text { is } \sqrt{41} .\]
APPEARS IN
संबंधित प्रश्न
Solve the equation –x2 + x – 2 = 0
Solve the equation x2 + 3x + 5 = 0
Solve the equation x2 – x + 2 = 0
Solve the equation `sqrt3 x^2 - sqrt2x + 3sqrt3 = 0`
Solve the equation `x^2 + x/sqrt2 + 1 = 0`
Solve the equation `x^2 -2x + 3/2 = 0`
Solve the equation 27x2 – 10x + 1 = 0
x2 + 2x + 5 = 0
\[x^2 + x + 1 = 0\]
\[17 x^2 - 8x + 1 = 0\]
\[x^2 + \frac{x}{\sqrt{2}} + 1 = 0\]
\[\sqrt{5} x^2 + x + \sqrt{5} = 0\]
\[- x^2 + x - 2 = 0\]
Solving the following quadratic equation by factorization method:
\[6 x^2 - 17ix - 12 = 0\]
Solve the following quadratic equation:
\[x^2 - \left( 5 - i \right) x + \left( 18 + i \right) = 0\]
Solve the following quadratic equation:
\[x^2 - \left( \sqrt{2} + i \right) x + \sqrt{2}i = 0\]
If \[2 + \sqrt{3}\] is root of the equation \[x^2 + px + q = 0\] than write the values of p and q.
Write the number of quadratic equations, with real roots, which do not change by squaring their roots.
If α, β are roots of the equation \[x^2 + lx + m = 0\] , write an equation whose roots are \[- \frac{1}{\alpha}\text { and } - \frac{1}{\beta}\].
If α, β are roots of the equation \[x^2 - a(x + 1) - c = 0\] then write the value of (1 + α) (1 + β).
For the equation \[\left| x \right|^2 + \left| x \right| - 6 = 0\] ,the sum of the real roots is
If a, b are the roots of the equation \[x^2 + x + 1 = 0, \text { then } a^2 + b^2 =\]
If α, β are roots of the equation \[4 x^2 + 3x + 7 = 0, \text { then } 1/\alpha + 1/\beta\] is equal to
The values of x satisfying log3 \[( x^2 + 4x + 12) = 2\] are
If α, β are the roots of the equation \[x^2 + px + 1 = 0; \gamma, \delta\] the roots of the equation \[x^2 + qx + 1 = 0, \text { then } (\alpha - \gamma)(\alpha + \delta)(\beta - \gamma)(\beta + \delta) =\]
The number of real solutions of \[\left| 2x - x^2 - 3 \right| = 1\] is
If the roots of \[x^2 - bx + c = 0\] are two consecutive integers, then b2 − 4 c is
If one root of the equation \[x^2 + px + 12 = 0\] while the equation \[x^2 + px + q = 0\] has equal roots, the value of q is
If α, β are the roots of the equation \[x^2 + px + q = 0 \text { then } - \frac{1}{\alpha} + \frac{1}{\beta}\] are the roots of the equation
If α, β are the roots of the equation \[x^2 - p(x + 1) - c = 0, \text { then } (\alpha + 1)(\beta + 1) =\]
The least value of k which makes the roots of the equation \[x^2 + 5x + k = 0\] imaginary is
Find the value of a such that the sum of the squares of the roots of the equation x2 – (a – 2)x – (a + 1) = 0 is least.
Show that `|(z - 2)/(z - 3)|` = 2 represents a circle. Find its centre and radius.
If `|(z - 2)/(z + 2)| = pi/6`, then the locus of z is ______.