मराठी

X2 + 2x + 5 = 0 - Mathematics

Advertisements
Advertisements

प्रश्न

x2 + 2x + 5 = 0

उत्तर

Given: 

\[x^2 + 2x + 5 = 0\]

\[x^2 + 2x + 5 = 0\]

\[ \Rightarrow x^2 + 2x + 1 + 4 = 0\]

\[ \Rightarrow (x + 1 )^2 - (2i )^2 = 0 [(a + b )^2 = a^2 + b^2 + 2ab]\]

\[ \Rightarrow (x + 1 + 2i) (x + 1 - 2i) = 0 [ a^2 - b^2 = (a + b) (a - b)]\]

\[\Rightarrow (x + 1 + 2i) = 0\] or \[(x + 1 - 2i) = 0\]

\[\Rightarrow x = - (1 + 2i)\] or, \[x = - 1 + 2i\]

Hence, the roots of the equation are \[- 1 + 2i \text { and } - 1 - 2i\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 14: Quadratic Equations - Exercise 14.1 [पृष्ठ ५]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 11
पाठ 14 Quadratic Equations
Exercise 14.1 | Q 3 | पृष्ठ ५

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Solve the equation 2x2 + x + 1 = 0


Solve the equation –x2 + x – 2 = 0


Solve the equation x2 + 3x + 5 = 0


Solve the equation  `sqrt2x^2 + x + sqrt2 = 0`


Solve the equation  `sqrt3 x^2 - sqrt2x + 3sqrt3 = 0`


Solve the equation `x^2 + x + 1/sqrt2 = 0`


If z1 = 2 – i,  z2 = 1 + i, find `|(z_1 + z_2 + 1)/(z_1 - z_2 + 1)|`


x2 + x + 1 = 0


\[x^2 - 4x + 7 = 0\]


\[x^2 + 2x + 5 = 0\]


\[x^2 - x + 1 = 0\]


\[21 x^2 - 28x + 10 = 0\]


\[13 x^2 + 7x + 1 = 0\]


\[\sqrt{2} x^2 + x + \sqrt{2} = 0\]


\[x^2 + x + \frac{1}{\sqrt{2}} = 0\]


\[x^2 + \frac{x}{\sqrt{2}} + 1 = 0\]


\[\sqrt{5} x^2 + x + \sqrt{5} = 0\]


\[3 x^2 - 4x + \frac{20}{3} = 0\]


Solving the following quadratic equation by factorization method:

\[x^2 + 10ix - 21 = 0\]


Solve the following quadratic equation:

\[x^2 + 4ix - 4 = 0\]


Solve the following quadratic equation:

\[i x^2 - x + 12i = 0\]


Solve the following quadratic equation:

\[2 x^2 - \left( 3 + 7i \right) x + \left( 9i - 3 \right) = 0\]


Write the number of real roots of the equation \[(x - 1 )^2 + (x - 2 )^2 + (x - 3 )^2 = 0\].


If roots α, β of the equation \[x^2 - px + 16 = 0\] satisfy the relation α2 + β2 = 9, then write the value P.


If a and b are roots of the equation \[x^2 - x + 1 = 0\],  then write the value of a2 + b2.


If a, b are the roots of the equation \[x^2 + x + 1 = 0, \text { then } a^2 + b^2 =\]


If x is real and \[k = \frac{x^2 - x + 1}{x^2 + x + 1}\], then


If the equations \[x^2 + 2x + 3\lambda = 0 \text { and } 2 x^2 + 3x + 5\lambda = 0\]  have a non-zero common roots, then λ =


The value of p and q (p ≠ 0, q ≠ 0) for which pq are the roots of the equation \[x^2 + px + q = 0\] are

 

The number of roots of the equation \[\frac{(x + 2)(x - 5)}{(x - 3)(x + 6)} = \frac{x - 2}{x + 4}\] is 


If α, β are the roots of the equation \[x^2 + px + q = 0 \text { then } - \frac{1}{\alpha} + \frac{1}{\beta}\] are the roots of the equation


If α, β are the roots of the equation \[x^2 - p(x + 1) - c = 0, \text { then } (\alpha + 1)(\beta + 1) =\]


The least value of which makes the roots of the equation  \[x^2 + 5x + k = 0\]  imaginary is


The equation of the smallest degree with real coefficients having 1 + i as one of the roots is


Find the value of P such that the difference of the roots of the equation x2 – Px + 8 = 0 is 2.


If 1 – i, is a root of the equation x2 + ax + b = 0, where a, b ∈ R, then find the values of a and b.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×