हिंदी

X2 + 2x + 5 = 0 - Mathematics

Advertisements
Advertisements

प्रश्न

x2 + 2x + 5 = 0

उत्तर

Given: 

\[x^2 + 2x + 5 = 0\]

\[x^2 + 2x + 5 = 0\]

\[ \Rightarrow x^2 + 2x + 1 + 4 = 0\]

\[ \Rightarrow (x + 1 )^2 - (2i )^2 = 0 [(a + b )^2 = a^2 + b^2 + 2ab]\]

\[ \Rightarrow (x + 1 + 2i) (x + 1 - 2i) = 0 [ a^2 - b^2 = (a + b) (a - b)]\]

\[\Rightarrow (x + 1 + 2i) = 0\] or \[(x + 1 - 2i) = 0\]

\[\Rightarrow x = - (1 + 2i)\] or, \[x = - 1 + 2i\]

Hence, the roots of the equation are \[- 1 + 2i \text { and } - 1 - 2i\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 14: Quadratic Equations - Exercise 14.1 [पृष्ठ ५]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 11
अध्याय 14 Quadratic Equations
Exercise 14.1 | Q 3 | पृष्ठ ५

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Solve the equation x2 + 3 = 0


Solve the equation –x2 + x – 2 = 0


Solve the equation x2 – x + 2 = 0


Solve the equation  `sqrt2x^2 + x + sqrt2 = 0`


Solve the equation 21x2 – 28x + 10 = 0


If z1 = 2 – i,  z2 = 1 + i, find `|(z_1 + z_2 + 1)/(z_1 - z_2 + 1)|`


\[4 x^2 + 1 = 0\]


\[5 x^2 - 6x + 2 = 0\]


\[21 x^2 + 9x + 1 = 0\]


\[x^2 - x + 1 = 0\]


\[17 x^2 + 28x + 12 = 0\]


\[21 x^2 - 28x + 10 = 0\]


\[2 x^2 + x + 1 = 0\]


\[x^2 - 2x + \frac{3}{2} = 0\]


Solving the following quadratic equation by factorization method:

\[x^2 + 10ix - 21 = 0\]


Solving the following quadratic equation by factorization method:

\[x^2 + \left( 1 - 2i \right) x - 2i = 0\]


Solving the following quadratic equation by factorization method:

\[x^2 - \left( 2\sqrt{3} + 3i \right) x + 6\sqrt{3}i = 0\]


Solving the following quadratic equation by factorization method:

\[6 x^2 - 17ix - 12 = 0\]

 

Solve the following quadratic equation:

\[x^2 - \left( 3\sqrt{2} + 2i \right) x + 6\sqrt{2i} = 0\]


Solve the following quadratic equation:

\[x^2 - \left( 2 + i \right) x - \left( 1 - 7i \right) = 0\]


Solve the following quadratic equation:

\[2 x^2 + \sqrt{15}ix - i = 0\]


Write the number of real roots of the equation \[(x - 1 )^2 + (x - 2 )^2 + (x - 3 )^2 = 0\].


If roots α, β of the equation \[x^2 - px + 16 = 0\] satisfy the relation α2 + β2 = 9, then write the value P.


If \[2 + \sqrt{3}\] is root of the equation \[x^2 + px + q = 0\] than write the values of p and q.


Write the number of quadratic equations, with real roots, which do not change by squaring their roots.


If α, β are roots of the equation \[x^2 - a(x + 1) - c = 0\] then write the value of (1 + α) (1 + β).


For the equation \[\left| x \right|^2 + \left| x \right| - 6 = 0\] ,the sum of the real roots is


If a, b are the roots of the equation \[x^2 + x + 1 = 0, \text { then } a^2 + b^2 =\]


The number of real roots of the equation \[( x^2 + 2x )^2 - (x + 1 )^2 - 55 = 0\] is 


If α, β are the roots of the equation \[a x^2 + bx + c = 0, \text { then } \frac{1}{a\alpha + b} + \frac{1}{a\beta + b} =\]


If α, β are the roots of the equation \[x^2 + px + 1 = 0; \gamma, \delta\] the roots of the equation \[x^2 + qx + 1 = 0, \text { then } (\alpha - \gamma)(\alpha + \delta)(\beta - \gamma)(\beta + \delta) =\]


If x is real and \[k = \frac{x^2 - x + 1}{x^2 + x + 1}\], then


If the roots of \[x^2 - bx + c = 0\] are two consecutive integers, then b2 − 4 c is


The value of a such that  \[x^2 - 11x + a = 0 \text { and } x^2 - 14x + 2a = 0\] may have a common root is


If α and β are the roots of \[4 x^2 + 3x + 7 = 0\], then the value of \[\frac{1}{\alpha} + \frac{1}{\beta}\] is


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×