मराठी

If One Root of the Equation X 2 + P X + 12 = 0 While the Equation X 2 + P X + Q = 0 Has Equal Roots, the Value of Q is - Mathematics

Advertisements
Advertisements

प्रश्न

If one root of the equation \[x^2 + px + 12 = 0\] while the equation \[x^2 + px + q = 0\] has equal roots, the value of q is

पर्याय

  •  49/4

  •  4/49

  • 4

  • none of these

MCQ

उत्तर

49/4
It is given that, 4 is the root of the equation \[x^2 + px + 12 = 0\].

\[\therefore 16 + 4p + 12 = 0\]

\[ \Rightarrow p = - 7\]

It is also given that, the equation

\[x^2 + px + q = 0\] has equal roots. So, the discriminant of \[x^2 + px + q = 0\] will be zero.

\[\therefore p^2 - 4q = 0\]

\[ \Rightarrow 4q = \left( - 7 \right)^2 = 49\]

\[ \Rightarrow q = \frac{49}{4}\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 14: Quadratic Equations - Exercise 14.4 [पृष्ठ १७]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 11
पाठ 14 Quadratic Equations
Exercise 14.4 | Q 16 | पृष्ठ १७

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Solve the equation 2x2 + x + 1 = 0


Solve the equation –x2 + x – 2 = 0


Solve the equation  `sqrt3 x^2 - sqrt2x + 3sqrt3 = 0`


Solve the equation `3x^2 - 4x + 20/3 = 0`


Solve the equation 21x2 – 28x + 10 = 0


x2 + 1 = 0


x2 + 2x + 5 = 0


\[4 x^2 + 1 = 0\]


\[5 x^2 - 6x + 2 = 0\]


\[21 x^2 + 9x + 1 = 0\]


\[17 x^2 - 8x + 1 = 0\]


\[17 x^2 + 28x + 12 = 0\]


\[21 x^2 - 28x + 10 = 0\]


\[2 x^2 + x + 1 = 0\]


\[\sqrt{3} x^2 - \sqrt{2}x + 3\sqrt{3} = 0\]


\[x^2 + x + \frac{1}{\sqrt{2}} = 0\]


\[3 x^2 - 4x + \frac{20}{3} = 0\]


Solve the following quadratic equation:

\[x^2 + 4ix - 4 = 0\]


Solve the following quadratic equation:

\[i x^2 - x + 12i = 0\]


Solve the following quadratic equation:

\[x^2 - \left( 3\sqrt{2} - 2i \right) x - \sqrt{2} i = 0\]


If \[2 + \sqrt{3}\] is root of the equation \[x^2 + px + q = 0\] than write the values of p and q.


If a and b are roots of the equation \[x^2 - x + 1 = 0\],  then write the value of a2 + b2.


For the equation \[\left| x \right|^2 + \left| x \right| - 6 = 0\] ,the sum of the real roots is


If a, b are the roots of the equation \[x^2 + x + 1 = 0, \text { then } a^2 + b^2 =\]


The number of real roots of the equation \[( x^2 + 2x )^2 - (x + 1 )^2 - 55 = 0\] is 


If α, β are the roots of the equation \[a x^2 + bx + c = 0, \text { then } \frac{1}{a\alpha + b} + \frac{1}{a\beta + b} =\]


The number of solutions of `x^2 + |x - 1| = 1` is ______. 


If x is real and \[k = \frac{x^2 - x + 1}{x^2 + x + 1}\], then


If the roots of \[x^2 - bx + c = 0\] are two consecutive integers, then b2 − 4 c is


The value of a such that  \[x^2 - 11x + a = 0 \text { and } x^2 - 14x + 2a = 0\] may have a common root is


The values of k for which the quadratic equation \[k x^2 + 1 = kx + 3x - 11 x^2\] has real and equal roots are


The value of p and q (p ≠ 0, q ≠ 0) for which pq are the roots of the equation \[x^2 + px + q = 0\] are

 

If α and β are the roots of \[4 x^2 + 3x + 7 = 0\], then the value of \[\frac{1}{\alpha} + \frac{1}{\beta}\] is


If the difference of the roots of \[x^2 - px + q = 0\]  is unity, then

 

If α, β are the roots of the equation \[x^2 - p(x + 1) - c = 0, \text { then } (\alpha + 1)(\beta + 1) =\]


The least value of which makes the roots of the equation  \[x^2 + 5x + k = 0\]  imaginary is


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×